Hello!
I am very new to MatLab. I am wondering, what is the simplest way to convert a 5-digit number into a matrix of those 5 digits.
Thanks,

3 commentaires

Image Analyst
Image Analyst le 9 Fév 2012
What do want as the output, numbers (integers, doubles, etc.) or characters?
student
student le 9 Fév 2012
I want to convert it to integers.
As in, 12345 into [ 1 , 2 , 3 , 4 , 5 ]
Andrei Bobrov
Andrei Bobrov le 10 Fév 2012
:)
fix(rem(TheNumber*10.^-(ceil(log10(TheNumber)):-1:1),1)*10)

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Réponses (2)

Walter Roberson
Walter Roberson le 9 Fév 2012

0 votes

sprintf('%d', TheNumber) - '0'
is the simplest, but not the most efficient.
Benjamin Schwabe
Benjamin Schwabe le 9 Fév 2012

0 votes

You can do that by simply using the following code:
p = 12345; % define your number
pstr=num2str(p);
n=length(pstr);
v=zeros(n,1);
for k=1:n
v(k)=str2double(pstr(k));
end
It will work for all integer numbers. For non Integer numbers, the "." will be transformed into 'NaN'.

2 commentaires

Benjamin Schwabe
Benjamin Schwabe le 9 Fév 2012
Maybe some more details:
I convert the number to a string with num2str, then I take each character of the string and transfort it back to a number.
If you want to have a row vector instead of a column, just replace
v=zeros(n,1); by v=zeros(1,n);
Walter Roberson
Walter Roberson le 10 Fév 2012
When you are dealing with single digits, subtracting the character '0' is much more efficient than str2double().

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le 9 Fév 2012

Modifié(e) :

le 8 Oct 2013

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