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How to replace values in a matrix?

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aya ben mabrouk
aya ben mabrouk le 6 Juin 2016
Commenté : aya ben mabrouk le 6 Juin 2016
Hello everyone, I am new in matlab and I need help please.
I have a matrix A that contains probability distribution( size : 7*8).there is the matrix :
A=[ 0.2 0.07 0.25 0.87 0.09 0.14 0.8 0.3;
0.1 0.5 0.25 0.14 0.98 0.025 0.58 0.11;
0.001 0.25 0.88 0.21 0.03 0.25 0.58 0.25;
0.26 0.58 0.001 0.06 0.9 0.58 0.44 0.15;
0.12 0.58 0.16 0.08 0.15 0.47 0.33 0.15;
0.15 0.22 0.3 0.14 0.01 0.99 0.77 0.55;
0.003 0.25 0.14 0.99 0.005 0.85 0.26 0.003;
];
I have also a matrix B (size 7*4) that contains such A probabilities and matrix C (size 7*4) that contains positions.
B=[ 0.25 0.55 0.15 0.02;
0.001 0.25 0.33 0.04;
0.2 0.3 0.11 0.58;
0.25 0.14 0.77 0.69;
0.88 0.59 0.58 0.001;
0.02 0.3 0.7 0.8;
0.3 0.9 0.66 0.11;]
C= [ 8 2 4 1
1 2 3 4
7 5 2 8
1 2 3 4
2 4 3 7
1 5 6 7
2 8 4 1]
My goal is to replace values in A with values in the matrix B according to the position in C, I will have as result this matrix (size 7*8) :
NewA=[ 0.02 0.55 0.25 0.15 0.09 0.14 0.08 0.25
0.001 0.25 0.33 0.04 0.98 0.025 0.58 0.11
0.001 0.11 0.88 0.21 0.3 0.25 0.2 0.58
0.25 0.14 0.77 0.69 0.9 0.58 0.44 0.15
0.12 0.88 0.58 0.59 0.15 0.047 0.001 0.15
0.02 0.22 0.3 0.14 0.21 0.7 0.8 0.55
0.11 0.3 0.14 0.66 0.005 0.85 0.26 0.9]
Please, any idea, How Can I do it? and thanks in advance

Réponse acceptée

Image Analyst
Image Analyst le 6 Juin 2016
Try a simple for loop:
A=[ 0.2 0.07 0.25 0.87 0.09 0.14 0.8 0.3;
0.1 0.5 0.25 0.14 0.98 0.025 0.58 0.11;
0.001 0.25 0.88 0.21 0.03 0.25 0.58 0.25;
0.26 0.58 0.001 0.06 0.9 0.58 0.44 0.15;
0.12 0.58 0.16 0.08 0.15 0.47 0.33 0.15;
0.15 0.22 0.3 0.14 0.01 0.99 0.77 0.55;
0.003 0.25 0.14 0.99 0.005 0.85 0.26 0.003;
];
B=[ 0.25 0.55 0.15 0.02;
0.001 0.25 0.33 0.04;
0.2 0.3 0.11 0.58;
0.25 0.14 0.77 0.69;
0.88 0.59 0.58 0.001;
0.02 0.3 0.7 0.8;
0.3 0.9 0.66 0.11;]
C= [ 8 2 4 1
1 2 3 4
7 5 2 8
1 2 3 4
2 4 3 7
1 5 6 7
2 8 4 1]
[rows, columns] = size(B)
newA = A; % Initialize.
for row = 1 : rows
newA(row, C(row,:)) = B(row, :);
end
newA % Print in command window to verify

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