Please Speed UP This Algoritm!!!
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hi i'd like to know if there's is a way to speed up this algoritm where:, lphi is a vector of 120 elements, IN4 is a matrix of 4x8192, aaa is a 3D matrix of 4x8192x120
for k = 1:lphi;
B4(k,:) = sum(IN4.*aaa(:,:,k));
end
B = sum(abs(B4).^2,2);
thanks, i don't know if in c++ it work faster any ideas?
2 commentaires
the cyclist
le 13 Fév 2012
It's not clear to me what your loop does. You say that lphi is a vector, but then you loop over k=1:lphi. That seems odd to me, and not really what you want.
Paolo Rossi
le 13 Fév 2012
Réponse acceptée
Plus de réponses (2)
Sean de Wolski
le 13 Fév 2012
bsxfun is lurking (update: and staying hidden)!
The fastest I could get it was to dynamically preallocate your for-loop.
for k = 120:-1:1
B5(k,:) = sum(IN4.*aaa(:,:,k));
end
B2 = sum(abs(B5).^2,2);
1 commentaire
Paolo Rossi
le 13 Fév 2012
James Tursa
le 13 Fév 2012
Another option you can try using some FEX submissions (slightly better at memory management than your original code):
uninit; % One time only, to built the mex routine
mtimesx; % One time only, to build the mex routine
B4 = uninit(8192,1,lphi); % Fast create variable
for k = 1:lphi;
B4(:,:,k) = sum(IN4.*aaa(:,:,k)).'; % Contiguous result
end
B = mtimesx(B4,'t',B4,'speedomp'); % Fast nD dot product
B = B(:); % Reshape result to column
You can find uninit and mtimesx here:
Note: This won't give exactly the same answer as the MATLAB code because the last dot product operation is done internally in mtimesx differently from MATLAB.
Q: Is everything real? What is the point of the abs( )?
3 commentaires
Paolo Rossi
le 13 Fév 2012
James Tursa
le 13 Fév 2012
In that case use 'c' instead of 't' in the mtimesx call. E.g.,
B = mtimesx(B4,'c',B4,'speedomp');
Paolo Rossi
le 13 Fév 2012
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