Find largest array size in cell of many arrays
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I have a cell each cell storing a different sized array. How do i find the largest width and height of all the arrays ?
I tried
size(test{:}(:,1,1))
test is my cell. so meaning for all test, find the size of (:,1,1). But it is wrong of coz so help me thanks.
Like
cell{1} = 10x10 uint8
cell{2} = 10x11
cell{3} = 5x99
so
min_size_of_cell_array(cell{:}) = 5,10
like that
1 commentaire
Stephen23
le 17 Juin 2016
>> C{1} = NaN(10,10);
>> C{2} = zeros(10,11);
>> C{3} = ones(5,99);
>> cellfun('size',C,1) % rows
ans =
10 10 5
>> cellfun('size',C,2) % columns
ans =
10 11 99
Réponse acceptée
Andrei Bobrov
le 17 Juin 2016
C = arrayfun(@(x)rand(randi([1 20],1,2)),(1:8)','un',0);% example
[s,d] = cellfun(@size,C);
out = max([s,d]);
2 commentaires
Avik Mahata
le 13 Jan 2019
How do I convert the maximum cellarray to matrix after identifying the particular cell array?
Plus de réponses (1)
shashmitha lakshmi
le 16 Jan 2020
How to find the maxmimum length array between two arrays
1 commentaire
Image Analyst
le 17 Jan 2020
Try this:
% Create our data, a cell array of vectors of random lengths.
for k = 1 : 100
thisLength = randi(50); % Anywhere from 1 to 50.
ca{k} = rand(1, thisLength); % Create row vector of this length.
end
% Now that data has been created,
% find the lengths of all the elements.
allLengths = cellfun(@length, ca)
% Now find the longest vector between element 15 and 35 (for example)
maxLength = max(allLengths(15:35))
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