"Assignment has more non-singleton rhs dimensions than non-singleton subscripts"

Hey all, having the problem "Assignment has more non-singleton rhs dimensions than non-singleton subscripts" as stated above.

Firstly, I know what this problem means and where the error is occuring, I just cannot figure out a solution for it.

My code is as followed:

 a0 = [0 0 0];
b0 = a0/3 .* [1 1 1];
a1 = a0/2 .* [0 1 1];
a2 = a0/2 .* [1 0 1];
a3 = a0/2 .* [1 1 0];
In = n .*a1 + m .*a2 + l .*a3;
P = n .*a1 + n .*a2 + l .*a3 + b0; 
for n = 1:5
    for m = 1:5
        for l = 1:5
            In(n+1,m+1,l+1,:) = a0;
            P(n+1,m+1,l+1,:) = a0 + b0;
        end
    end
end

The error occurs in:

In(n+1,m+1,l+1,:) = a0;

[Thomas]

I've solved it!

Working code is:

a0 = [0 0 0];
b0 = a0/3 .* [1 1 1];

a1 = a0/2 .* [0 1 1];
a2 = a0/2 .* [1 0 1];
a3 = a0/2 .* [1 1 0];

In = n .*a1 + m .*a2 + l .*a3;
P = n .*a1 + n .*a2 + l .*a3 + b0; 

for n = 1:5
    for m = 1:5
        for l = 1:5
            In(n+1,m+1,l+1,1:3) = a0';
            P(n+1,m+1,l+1,1:3) = a0' + b0';
        end
    end
end

[Torsten]

Note that the lines

In = n .*a1 + m .*a2 + l .*a3;
P = n .*a1 + n .*a2 + l .*a3 + b0;

are superfluos and that you can get the same result for In and P if you just initialize them to zero:

In = zeros(6,6,6,3);
P = zeros(6,6,6,3);

Best wishes

Torsten.

[Thomas]

Thanks Torsten, I'm always looking for ways to improve my coding!