How can i minimize

4 vues (au cours des 30 derniers jours)
Jeffrey Eiyike
Jeffrey Eiyike le 23 Juin 2016
min h
45<= x1 + u1 -u3 -u4 <= 45 + h100
40<= x2 + u2 -u3 +u4 <= 40 + h100
80<= x3 + u3 <= 80 + h100
u1,u2,u3,u4 >= 0
u1<= 170 ,u2<= 50 , u3<= 100, u4<= 70
  1 commentaire
Torsten
Torsten le 24 Juin 2016
What does h100 mean ? How is it related to h ?
Best wishes
Torsten.

Connectez-vous pour commenter.

Réponses (4)

Titus Edelhofer
Titus Edelhofer le 23 Juin 2016
Hi Jeffrey,
there is probably some missing information. I guess it's clear that h>=0. Since there are no restrictions on x1, x2, x3, you might choose
u1 = 0; u2 = 0; u3 = 0; u4 = 0;
x1 = 45; x2 = 40; x3 = 80;
=>
h = 0;
is the optimal solution... ? Or am I missing something?
Titus
  1 commentaire
Jeffrey Eiyike
Jeffrey Eiyike le 23 Juin 2016
I am suppose to minimise h .

Connectez-vous pour commenter.


Jeffrey Eiyike
Jeffrey Eiyike le 23 Juin 2016
That's the question on the jpg

Titus Edelhofer
Titus Edelhofer le 24 Juin 2016
Hi Jeffrey,
I'm not sure I fully understand. If u1, u2, u3, u4 and x (=x1,x2,x3) are given, the computing lambda is trivial. There is still some information missing.
Titus
  1 commentaire
Jeffrey Eiyike
Jeffrey Eiyike le 24 Juin 2016
u1<= 170 ,u2<= 50 , u3<= 100, u4<= 70 and x1= 130 x2= 120 x3= 150

Connectez-vous pour commenter.


Titus Edelhofer
Titus Edelhofer le 24 Juin 2016
Hi Jeffrey,
if I'm not mistaken, this should work:
% let the vector of unknowns be [u1 u2 u3 u4 lambda], then we
% have the following inequalities:
% u1 -u3 -u4 -lambda*100 <= 45-x1
% -u1 +u3 +u4 <= -45+x1
% and likewise for the other two
% in matrix form A*x<=b we have:
A = [ ...
1 0 -1 -1 -100;
0 1 -1 1 -100;
0 0 1 0 -100;
-1 0 1 1 0;
0 -1 1 -1 0;
0 0 -1 0 0];
% where b is:
b = [45-130; 40-120; 80-150; -45+130; -40+120; -80+150];
% now solve for the unknowns: we don't care about u1, u2, u3, u4 but lambda should be small:
uLambda = linprog([0;0;0;0;1], A, b, [], [], [0;0;0;0;0], [170;50;100;70;inf])
% extract lambda
lambda = uLambda(5);
Titus

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by