how to convert 2d to id

i want to convert a 5x3 matrix say A into 1d but before reshaping it i need to omit certain values from every row of A.number of values i need to omit is given in another matrix say C. for eg

A=[5 4 3 8 9 6; 2 1 3 2 5 ;4 3 5 7 6]
C=[1; 3; 4]

what i need is to convert matrix A into an array such that from first row of A last one value is to be emitted from second row last 3 values are to be removed and similarly from third row last 4 values need to be omitted. number of values to be omitted is given in row matrix C

please help

[Azzi Abdelmalek]

You omitted to show us the expected result

[Stephen23]

@studentambitious: your matrix A generates this error:

>> A=[5 4 3 8 9 6; 2 1 3 2 5 ;4 3 5 7 6]
Error using vertcat
Dimensions of matrices being concatenated are not consistent.

Answer 1

[KSSV]

A=[5 4 3 8 9 ; 2 1 3 2 5 ;4 3 5 7 6] ;
B = [1 3 4] ;

iwant = fliplr(A) ;
for i = 1:length(B)
    id = B(i) ;
    iwant(i,1:id) = NaN  ;
end
iwant = fliplr(iwant) ;
idx = ~isnan(iwant) ;
iwant = iwant(idx) ;

Answer 2

[Azzi Abdelmalek]

A=[5 4 3 8 9 ; 2 1 3 2 5 ;4 3 5 7 6]
C=[1; 3; 4]
n=size(A,2);
m=numel(C);
out=A(:);
idx=arrayfun(@(x) sub2ind(size(A),x*ones(1,C(x)),n:-1:n-C(x)+1),(1:m),'un',0)
idx=cell2mat(idx)
out(idx)=[]

%Or

A=[5 4 3 8 9 ; 2 1 3 2 5 ;4 3 5 7 6];
C=[1; 3; 4];
[n,m]=size(A);
B=zeros(1,n*m-sum(C));
idx=1;
for k=1:n
  kk=1:m-C(k);
  p=numel(kk);
  B(1,idx:idx+p-1)=A(k,kk);
  idx=idx+p;
end
B

Answer 3

[José-Luis]

Probably faster:

A=[5 4 3 8 9 ; 2 1 3 2 5 ;4 3 5 7 6];
C=[1; 3; 4];

numCol = size(A,2);
A(bsxfun(@gt,numCol - C,1:numCol)) = NaN

Please note that you did not specify how you wanted your results stored. Here, I replace the unnecessary data with NaN.