Effacer les filtres
Effacer les filtres

Any ideas how i can reduce the execution time?

1 vue (au cours des 30 derniers jours)
Dennis_Pana
Dennis_Pana le 19 Juil 2016
newdes=[0.6250 0.8750; 0.2500 0.7500; 0.3750 0.1250;
0.8750 0.3750; 0.1250 0.6250; 0 0; 0.5000 0.5000; 0.7500 0.2500;
0.6875 0.0625; 0.0625 0.8125; 0.1875 0.6875; 0.3125 0.3125;
0.4375 0.9375; 0.5625 0.5625; 0.9375 0.1875; 0.8125 0.4375;] ;
dis=zeros(v,1);
v=16;
m=2;
sum=0
s=2;
for j=1:v
for k=1:m
ddii=(newdes(s,k)-newdes(j,k))^2;%Distance calculation of point s at its new location with all the other points.
sum=sum+ddii;
end
dis(j,1)=sum; %Store all the distances.
sum=0;
end
I am trying to use bxsfun, but i cannot solve it. I want reduce the time effort. Thank you in advance.

Réponse acceptée

Dennis_Pana
Dennis_Pana le 20 Juil 2016
xx=bsxfun(@minus,newdes(s,:),newdes(1:v,:));
sbs=xx.^2;
dis(:,1)=sum(sbs,2);
That is what i was looking for.

Plus de réponses (1)

Azzi Abdelmalek
Azzi Abdelmalek le 19 Juil 2016
newdes=[0.6250 0.8750; 0.2500 0.7500; 0.3750 0.1250;
0.8750 0.3750; 0.1250 0.6250; 0 0; 0.5000 0.5000; 0.7500 0.2500;
0.6875 0.0625; 0.0625 0.8125; 0.1875 0.6875; 0.3125 0.3125;
0.4375 0.9375; 0.5625 0.5625; 0.9375 0.1875; 0.8125 0.4375;] ;
[nn,mm]=size(newdes)
v=16;
m=2;
s=2;
ay=repmat(1:m,1,v)
ax=s*ones(1,numel(ay))
idx1=sub2ind([nn mm],ax',ay')
[xx,yy]=meshgrid(1:v,1:m)
idx2=sub2ind([nn mm],xx(:),yy(:))
ww=(newdes(idx1)-newdes(idx2)).^2 %Distance calculation of point s at its new location with all the other points.
dis1=sum(reshape(ww,2,[]))'
  5 commentaires
Azzi Abdelmalek
Azzi Abdelmalek le 19 Juil 2016
Modifié(e) : Azzi Abdelmalek le 19 Juil 2016
I made some improvement, but it's less faster. Sometimes for loop is more efficient!
[nn,mm]=size(newdes);
s=2;
ay=repmat(1:mm,nn,1);
ax=s*ones(size(ay));
idx1=reshape(sub2ind([nn mm],ax',ay'),mm,[]);
[xx,yy]=meshgrid(1:v,1:m);
idx2=sub2ind([nn mm],xx,yy);
ww=(newdes(idx1)-newdes(idx2)).^2 ; %Distance calculation of point s at its new location with all the other points.
dis1=sum(ww)';
Dennis_Pana
Dennis_Pana le 19 Juil 2016
Thank you for your effort. I will try to find a way to improve the time efficiency. Thanks again

Connectez-vous pour commenter.

Catégories

En savoir plus sur Descriptive Statistics dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by