How to bin a simple number array?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
That One
le 25 Juil 2016
Commenté : Steven Lord
le 26 Juil 2016
Hello,
I'm reading a simple number array from a .txt file (all integers) using:
fileID = fopen('control.txt','r');
formatSpec = '%d';
A = fscanf(fileID,formatSpec);
Now I want to bin these integers into a several groups:
Group 1: integers from 21 to 100;
Group 2: integers from 101 to 500;
Group 3: integers from 501 to 1000;
Group 4: integers from 1001 to infinity (max number unknown).
I'm also interested in finding the range (how many numbers) of each group.
Thank you!
0 commentaires
Réponse acceptée
Azzi Abdelmalek
le 25 Juil 2016
A=1:120
[b,c]=histc(A,[21 50 60 100 inf])
out=accumarray(c'+1,(1:numel(c))',[],@(x) {A(x)})
out=out(2:end)
celldisp(out)
Plus de réponses (1)
Steven Lord
le 25 Juil 2016
Use the histcounts function and specify a vector of edges.
4 commentaires
Star Strider
le 26 Juil 2016
You have already come close to defining them:
Group 1: integers from 21 to 100;
Group 2: integers from 101 to 500;
Group 3: integers from 501 to 1000;
Group 4: integers from 1001 to infinity (max number unknown).
Use the max function to help you define the upper edge.
Experiment with to get the result you want.
Voir également
Catégories
En savoir plus sur Matrices and Arrays dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!