Getting the minimum value from a row vector

Hi, I am calculating a min value in a row vector one after the other. There are two repetitions in the row vector. I want to pick 3 and 6 twice. The way i am doing is like this but it doesn't take care of the repetition in the vector

a=[1,2,3,3,4,5,6,6,7,8,9,10];
min_value=0;
for i=1:length(a)
    min_value=min(a(a>min_value));
end

[Adam]

What exactly is the result you are looking for? Your code currently gives an error when I paste it into Matlab so I can't even see what your current code is giving.

[Aftab Ahmed Khan]

Well, i'm sorry as i don't know that why it is giving you an error but it working fine with me. If you see in the vector, 3 and 6 is repeated. I want that the min function somehow should return the 3 and 6 twice.

[Stephen23]

@Aftab Ahmed Khan: your code:

a = [1,2,3,3,4,5,6,6,7,8,9,10];
min_value = 0;
for k = 1:length(a)
    min_value = min(a(a>min_value));
end

Give this error:

Error using  > 
Matrix dimensions must agree.

Error in Untitled1 (line 6)
    min_value = min(a(a>min_value));

because on twelfth iteration min_value is empty and so the comparison tries to compare an empty array with a 1x12 array. Thus the error.

"I want that the min function somehow should return the 3 and 6 twice."

Your code does not "return" or store any values, so it is not clear what you want.

[Aftab Ahmed Khan]

Well, i am running it with a breakpoint and didn't run it up to the twelfth iteration and didn't notice the error. Thanx. On the third iteration, min_value is 3 and on the fourth iteration it picks the value 4, skipping the 2nd 3 value. Similarly for the value 6.

[Aftab Ahmed Khan]

I have made the necessary changes to the code.

a=[1,2,3,3,4,5,6,6,7,8,9,10];
min_value=0;
for i=1:length(a)
    if isempty(min_value)
        break;
    end
    min_value=min(a(a>min_value))
end

Answer 1

[Stephen23]

Why make it complicated ?

>> a = [1,2,3,3,4,5,6,6,7,8,9,10];
>> b = sort(a); % guarantees the order
>> for k = 1:numel(b), disp(b(k)), end

Answer 2

[Stephen23]

a = [1,2,3,3,4,5,6,6,7,8,9,10];
f = find([1,diff(a),1]);
x = f(2:end)-f(1:end-1);
c = mat2cell(a,1,x);

where

>> c{:}
ans =
     1
ans =
     2
ans =
     3     3
ans =
     4
ans =
     5
ans =
     6     6
ans =
     7
ans =
     8
ans =
     9
ans =
    10