Effacer les filtres
Effacer les filtres

How to create a graph with X, Y + Contour Axes.

2 vues (au cours des 30 derniers jours)
Al Onen
Al Onen le 20 Fév 2012
Modifié(e) : Matt J le 25 Oct 2013
Hello, I need some guidance for creating a very similar chart shown below in the link.
For each axis, including the contoured one, I also have some data between 0-1 (actally % values) of corresponding type and I am supposed to show them in a single chart. I am not sure about how to combine those different values into one. If someone can offer some guidance with key functions, I would be greatly faithful.
Thanks in advance.

Réponse acceptée

the cyclist
the cyclist le 20 Fév 2012
Here is a simple example, which I hope you can bend to your needs. I adapted it from the documentation here: http://www.mathworks.com/help/techdoc/ref/contour.html. I think it illustrates most of what you want, including how to overlay multiple plots (with the hold command), adding labels to the contours, etc. There are help files for all the different functions I used, of course.
figure
hold on
[X,Y] = meshgrid(-2:.2:2,-2:.2:3);
Z = X.*exp(-X.^2-Y.^2);
[C,h] = contour(X,Y,Z);
set(h,'ShowText','on','TextStep',get(h,'LevelStep')*2)
addedRandomX = rand(1,20);
addedRandomY = rand(1,20);
plot(addedRandomX, 1+addedRandomY,'kx')
plot(-addedRandomX,1+addedRandomY,'ro')
  5 commentaires
the cyclist
the cyclist le 26 Fév 2012
The reason you got the mldivide error when calculating Z is that you were using the syntax for matrix division, where you actually wanted element-by-element division.
Try this instead:
figure
hold on
[X,Y] = meshgrid(-2:.2:2,-2:.2:3);
Z = 1./((1./(1-Y))+(1./X)-1);
[C,h] = contour(X,Y,Z)
Notice that I added "./" in place of just "/". The dots are the syntax for element-by-element operations.
I'm not sure if the result is what you expect, but at least it executes.
Al Onen
Al Onen le 26 Fév 2012
Thank you so much. Indeed it works - I'm such a loser with Matlab. :) I have to keep the purpose of dots in mind. Now the answer is officially accepted.

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Al Onen
Al Onen le 21 Fév 2012
Thank you, that will probably do the trick.

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