How to replace the matching cell
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Mekala balaji
le 6 Août 2016
Modifié(e) : Walter Roberson
le 9 Août 2016
Hi,
I have the below cell matrix,
pass OK Out OK OK Out
pass OK Out OK OK Out
fail OK Out OK OK Out
pass OK Out OK OK Out
pass OK Out OK OK Out
fail OK Out OK OK Out
If in first column of particular row is "fail" then replace the Out as "Outspec". Kindly someone help how to do this.
4 commentaires
Stephen23
le 8 Août 2016
Modifié(e) : Stephen23
le 8 Août 2016
Your input and output arrays do not match, according to your description: your output has "Out" in position (4,5), but the input does not. Where does this "Out" come from ?
Also in columns four and five you have three "OutSpec", but your input array does not show any "Out"s in those columns, as they both contain only "OK"s, and you did not mention that you want to do anything with "OK". Where did these "OutSpecs"s come from?
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Stephen23
le 8 Août 2016
Modifié(e) : Stephen23
le 8 Août 2016
This might do what you want:
inp = {...
'pass','OK','Out','OK','OK','Out';...
'pass','OK','Out','OK','OK','Out';...
'fail','OK','Out','Out','OK','Out';...
'pass','OK','Out','OK','OK','Out';...
'pass','OK','Out','OK','OK','Out';...
'fail','OK','Out','Out','Out','Out';...
}; % from your comment above
out = inp;
idx = strcmp(out(:,1),'fail');
out(idx,2:end) = strrep(out(idx,2:end),'Out','OutSpec')
output:
out =
'pass' 'OK' 'Out' 'OK' 'OK' 'Out'
'pass' 'OK' 'Out' 'OK' 'OK' 'Out'
'fail' 'OK' 'OutSpec' 'OutSpec' 'OK' 'OutSpec'
'pass' 'OK' 'Out' 'OK' 'OK' 'Out'
'pass' 'OK' 'Out' 'OK' 'OK' 'Out'
'fail' 'OK' 'OutSpec' 'OutSpec' 'OutSpec' 'OutSpec'
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Plus de réponses (1)
Walter Roberson
le 6 Août 2016
mask = strcmp(YourCell(:,1), 'fail');
YourCell(mask,[3 6]) = {'Outspec'};
3 commentaires
Walter Roberson
le 6 Août 2016
The entire row is not changed. Only columns 3 and 6 are changed. Did you try the code?
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