how i average n values in array

if i have data a and i want to mean or average every 10 values as 1:10, 2:11, 3:12 and as so on for length of data ?

Answer 1

[Walter Roberson]

mean(reshape(YourData, 10, []))

[yasmeen hadadd]

Thank you so much

[yasmeen hadadd]

But i need overlap between the values as 1:10 then from 2:11 and so on

[Mudassir Rafi]

arr=1:100;
for i=1:91
    a=(arr(i:i+9));
    mean(a)
end

[yasmeen hadadd]

please solve this error "Index exceeds matrix dimensions".

[Mudassir Rafi]

value of i should be 9 less than the last dimension of array (i.e.a in your case)

[Walter Roberson]

cs = cumsum(YourData);
moving_average = (cs(10:end) - cs(1:end-9))/10;

[Andrei Bobrov]

Hi Walter! Small correcting.

cs = cumsum(YourData(:));
moving_average = (cs(10:end) - [0;cs(1:end-10)])/10;

[Walter Roberson]

Thanks, Andrei

Answer 2

[Star Strider]

‘But i need overlap between the values as 1:10 then from 2:11 and so on’

Use a moving average filter:

Heart_pulse_avg = filter(ones(1,10), 10, Heart_pulse);

[Steven Lord]

Use the movmean function if you're using release R2016a or later.

Answer 3

[Andrei Bobrov]

a - your vector;

out = movsum(a,[0 9],'Endpoints','discard')/10;