HOW TO TAKE AVERAGE OF ROW AND COLUMN AT SOME POINT
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abdul wahab aziz
le 24 Août 2016
Commenté : abdul wahab aziz
le 24 Août 2016
I HAVE A MATRIX
2 5 3 500 4 5,
3 4 2 2 3 5,
4 5 5 1 2 2
code must scan first where 500 exists and take average of that row and column wher 500 exists excluding that 500,
here ans should be like avg row at first 2+5+3+4+5/5 and avg col of that point 2+1/2,
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Réponse acceptée
Star Strider
le 24 Août 2016
This works:
M = [2 5 3 500 4 5
3 4 2 2 3 5
4 5 5 1 2 2];
[r,c] = find(M == 500);
RowAvg = mean(M(r,M(r,:)~=500));
ColAvg = mean(M(M(:,c)~=500,c));
3 commentaires
Star Strider
le 24 Août 2016
The ‘r’ and ‘c’ are the row and column indices of ‘500’ respectively.
In the event of more than one ‘500’, the easiest way to modify my code would be to add a loop:
M = [2 5 3 500 4 5
3 4 2 2 3 5
4 5 500 1 2 2];
[r,c] = find(M == 500);
for k1 = 1:size(r,1)
RowAvg(k1) = mean(M(r(k1),M(r(k1),:)~=500));
ColAvg(k1) = mean(M(M(:,c(k1))~=500,c(k1)));
end
Here, every ‘[r,c]’ pair defines a specific value for ‘RowAvg’ and ‘ColAvg’.
This works if there is only one ‘500’ in any specific row or column. If there are more than one ‘500’ in any row or column, you have to decide how you want to deal with the second ‘500’.
Plus de réponses (1)
Thorsten
le 24 Août 2016
Modifié(e) : Thorsten
le 24 Août 2016
A = [2 5 3 500 4 5; 3 4 2 2 3 5; 4 5 5 1 2 2];
[i, j] = ind2sub(size(A), find(A==500));
m1 = mean(A(i, ~ismember(1:size(A,2), j)));
m2 = mean(A(~ismember(1:size(A,1), i), j));
A(i,j) = (m1 + m2)/2;
or
idx = A == 500
A(idx) = nan;
A(idx) = mean([nanmean(A(:, any(idx, 1))) nanmean(A(any(idx, 2), :), 2)])
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