Effacer les filtres
Effacer les filtres

How can I change multiple variable name within a loop, while assigning those variables as matrix values?

1 vue (au cours des 30 derniers jours)
I have a n x 3 matrix called dataMat. I also have n amount of processes that this code will eventually be able to handle. Each process has a n value (n), pressure (p) and volume (v). I want to be able to calculate the work done using 1 of two formulas-formula chosen based on if n=1 or not. My code is below, I don't know how to change the variable names while pulling data from the matrix at the same time.
n=size(dataMat,1);
for i=1:n
Cyc(i)n=dataMat(n,1);
Cyc(i)p=dataMat(n,2);
Cyc(i)v= dataMat(2,3);
end
formulas: if n=1 W=(P1)(V1)ln(V2/V1)
if not W=(P2*V2-P1*V1)/1-n1
  3 commentaires
Krish Desai
Krish Desai le 5 Sep 2016
Your edits to #1 are correct. #2 is correct as is, with (1-n1) as the denominator.

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Réponse acceptée

Walter Roberson
Walter Roberson le 4 Sep 2016

Plus de réponses (1)

John BG
John BG le 5 Sep 2016
the initial extraction does not need a for loop:
Cyc_n=dataMat(:,1);
Cyc_p=dataMat(:,2);
Cyc_v=dataMat(:,3);
Since it looks like the syntax of the formulas needs improving, I guess your are trying to differentiate,
W=zeros(1,length(Cyc_v))
for k=2:1:length(Cyc_n)
W(k-1)=Cyc_p(k-1)*Cyc_v(k-1)*log(Cyc_v(k)/Cyc_v(k-1))
end
or
for k=2:1:length(Cyc_n)
W(k-1)=Cyc_p(k)*Cyc_v(k)-Cyc_p(k-1)*Cyc_v(k-1)/(Cyc_n(k)-Cyc_n(k));
end
Krish, if you find this answer useful would you please be so kind to mark my answer as Accepted Answer?
To any other reader, please if you find this answer of any help solving your question,
please click on the thumbs-up vote link,
thanks in advance
John BG

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