
My rectangle should have a determined color represented by a value
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I have 2 patch objects which should be placed with a determined color (represented by a value). I did not implement it because I dont know how it works. So the rectangle 1 should have the value 50 and the rectangle 2 should have the value 75. The colorbar should start from 0 to 100. Thank you in advance.
v = [0 0; 1 0; 1 1; 0 1;5 5; 10 5;10 10;5 10];%Rectangle 1 and 2
f = [1 2 3 4; 5 6 7 8];
patch('Faces',f,'Vertices',v,'FaceColor','green')
colorbar
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Réponse acceptée
Stephen23
le 5 Sep 2016
Modifié(e) : Stephen23
le 5 Sep 2016
V = [0,0;1,0;1,1;0,1;5,5;10,5;10,10;5,10];
F = [1,2,3,4;5,6,7,8];
C = [50;75];
patch('Faces',F,'Vertices',V,'FaceVertexCData',C,'FaceColor','flat')
colormap(parula)
colorbar
caxis([0,100]) % set the color limits

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1 commentaire
Neda
le 8 Nov 2017
How about if we need to change the colour of circle based on their values, and circle superimposed on the image with rectangle which does have 'Curvature',[1 1].
Plus de réponses (1)
Thorsten
le 5 Sep 2016
Modifié(e) : Thorsten
le 5 Sep 2016
50 and 75 are not valid colorvalues in Matlab. Valid is an RGB triplet in the range [0, 1]. So I assumed that 50 and 75 is an index into a colormap. I choose 'gray', but you can any other valid colormap, like 'parula' or 'jet', for example:
Nfaces = 2;
facecolind = [50 70];
cmap = gray(100);
for i = 1:Nfaces
patch('Faces',f(i,:),'Vertices',v,'FaceColor', cmap(facecolind(i),:))
end
colormap(cmap)
h = colorbar
h.TickLabels = h.Ticks*100
3 commentaires
Adam
le 5 Sep 2016
Sounds like you want the jet colourmap then. You could create your own to be more to your taste, but jet does run from blue through green up to red.
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