Réponses (1)

Andrei Bobrov
Andrei Bobrov le 25 Fév 2012

0 votes

please read about function roots
or use function solve from Symbolic Math Toolbox
eg
use roots
%polynomial x^3-6*x^2-50*x-4
p = [1 -6 -50 -4]
out = roots(p)
use solve and Symbolic Math Toolbox
syms x
out2 = solve(x^3-6*x^2-50*x-4)
vpa(out2,6)
on Nasir comment
out = zeros(3,...);
for j1 = 1:....
B = ...
A = ...
out(:,j1) = roots([1, B-1, A-3*B^2, A*B-B^2-B^3]);
end

5 commentaires

Nasir Qazi
Nasir Qazi le 25 Fév 2012
if I have equation like this
Z^3 +(B-1)Z^2 +(A-3B^2)Z -(AB-B^2-B^3)=0
where the values of A & B are varies in iteration .
in that case how can I calculate the Roots ?
Walter Roberson
Walter Roberson le 25 Fév 2012
Careful, there would be three roots for each cubic, so you would not be able to store the output of roots() in to a single array location out(j1)
Andrei Bobrov
Andrei Bobrov le 25 Fév 2012
Thank you Walter! Corrected.
Nasir Qazi
Nasir Qazi le 27 Fév 2012
I have a condition of trail and error which will repeat the process of roots find after a condition of error checking , but after 10 iteration it give me a error , root input cannot be inf or nan , where exactly do I have a fault in the coding ... ?
Walter Roberson
Walter Roberson le 27 Fév 2012
I think we would need to see the code.

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le 25 Fév 2012

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le 25 Oct 2013

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