Hi,
I have a 3x3 cell as follows: [[1x40], [1x40], [1x40] ; [1x30], [1x30] ,[1x30] ; [1x50], [1x50] ,[1x50] ]
I would like to arrange the data, so that the final result is a 1x3 cell: [[3x40];[3x30];[3x50]]
I would like to do this without calling each cell specifically (in reality this is for a 20x20 cell)
Thanks

 Réponse acceptée

Walter Roberson
Walter Roberson le 14 Sep 2016

1 vote

arrayfun(@(col) vertcat(YourCell{:,col}), 1:size(YourCell,2), 'Uniform', 0)

2 commentaires

Isma_gp
Isma_gp le 16 Sep 2016
Hey, Thanks for your answer. The vertical concatenation is not working because the dimension of the cells in each row is different i.e. 30,40 and 50
arrayfun(@(row) vertcat(YourCell{row,:}), (1:size(YourCell,1)).', 'Uniform', 0)

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Plus de réponses (1)

Stephen23
Stephen23 le 16 Sep 2016
Modifié(e) : Stephen23 le 16 Sep 2016

0 votes

C = {...
rand(1,40),rand(1,40),rand(1,40);...
rand(1,30),rand(1,30),rand(1,30);...
rand(1,50),rand(1,50),rand(1,50)};
%
D = cellfun(@(c)vertcat(c{:}),num2cell(C,2),'UniformOutput',false);
and tested:
>> size(D{1})
ans =
3 40
>> size(D{2})
ans =
3 30
>> size(D{3})
ans =
3 50

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