Trying to make a "snake" matrix?

N=5;
M=9;
T=zeros(N,M);
count=0;
for i=1:N
    for j=1:M
        count=count+1;
        T(i,j)=count;
        if mod(i,2)==0
            T(i,j)=fliplr(T(i,j));
        end 
    end
end
T

I'm trying to get the even rows to go 1,2,3,4 and so on to the last column, and then on the even rows I want the elements to flip from left to right. SO far I've got a matrix that goes from 1 to the last element, and I can't seem to get the even rows to flip. Thanks!

[David Goodmanson]

Hello TG, 'fliprl' is not working because you are applying it to individual matrix elements T(i,j). Since T(i,j) is just a number, fliprl gives back that same number and doesn't do anything. You need to apply fliprl to an entire row.

[Tatiana Gospe]

Thanks!!

Answer 1

[Thorsten]

N = 5; M = 9;
T = reshape(1:M*N, [M, N])';
T(2:2:end,:) = fliplr(T(2:2:end,:));

Answer 2

[Andrei Bobrov]

N=5;
M=9;
T = reshape(1:N*M,N,[]);
T(:,2:2:end) = T(end:-1:1,2:2:end);

or

T = reshape(1:N*M,M,[])';
T(2:2:end,:) = T(2:2:end,end:-1:1);