What is the logic behind fzero and fsolve which make fsolve's speed faster than fzero?

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What is the logic behind fzero and fsolve which make fsolve's speed faster than fzero? Suppose that there is a polynomial equation, it can be solved by root function in shortest time, following by fsolve and fzero. Why is it so?

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Massimo Zanetti
Massimo Zanetti le 12 Oct 2016
Modifié(e) : Massimo Zanetti le 12 Oct 2016
The functions fsolve and fzero are not meant to solve the same problem. Specifically:
  1. fzero: It finds the root of a function (of one variable) in an interval [a,b]. It REQUIRES that f(a)*f(b)<0. fzeros uses a combination of bisection, secant, and inverse quadratic interpolation methods. Not every polynomial can be rooted by fzero: for instance x^2 doesn't work, because it has no sign change.
  2. fsolve: solves a SYSTEM of non-linear equations F(x) where x is multivariate. It use three different methods 'trust-region-dogleg' (default), 'trust-region', and 'levenberg-marquardt', depending on user needs.
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Dariusz Skibicki
Dariusz Skibicki le 23 Mar 2021
Thank you very much. The only sensible and simple answer. The only thing missing is the fact that fsolve is a Newtonian method.

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