looking for an explicit answer to my integral
Afficher commentaires plus anciens
Dear All,
In order to solve a physical problem, I need an explicit answer to the following integral: int(asin(1-1/x))
now I realize than an explicit answer might not exist and so that is perhaps why the 'int' function does not work. but I was wondering if you guys any suggestions for me as to how approach this problem and whether making approximations or assumptions would work?
Thanks, - Amir
Réponses (5)
Walter Roberson
le 29 Fév 2012
int(arcsin(1-1/x),x=a..b) assuming a::real, b::real, a<=b
piecewise(a < b, piecewise(b < 0, arcsin((-1+b)/b)*b+(-1+2*b)^(1/2), b = 0, I, 0 < b, arcsin((-1+b)/b)*b-(-1+2*b)^(1/2))+piecewise(And(0 < b, a < 0), 2*I, 0)+piecewise(a < 0, -arcsin((-1+a)/a)*a-(2*a-1)^(1/2), a = 0, I, 0 < a, -arcsin((-1+a)/a)*a+(2*a-1)^(1/2)), b = a, 0)
In the above, "I" is sqrt(-1)
If your domain of integration is complex, then probably things get messy.
Decoding the piecewise: if the limits of integration are both on the same side of 0, then
b * arcsin(1-1/b) - a * arcsin(1 - 1/a) - (sqrt(2*b - 1) - sqrt(2*a-1))
and if they are on different sides of 0, then add 2*I to the above result.
If either of the limits of integration can be exactly 0 then the result gets more complicated.
2 commentaires
Amir
le 29 Fév 2012
Walter Roberson
le 29 Fév 2012
Your brackets do not match. You have more '(' than ')'
I do not seem to be able to locate any useful conversions for you for this more general case; sorry.
UJJWAL
le 29 Fév 2012
0 votes
The explicit closed form answer exists. It is following ,
a * (cos(1)*ci(1/x) + sin(1)*si(1/x)+x*sin(1)*cos(1/x)-x*cos(1)*sin(1/x))
Here , ci(x) means cosine Integral of x. si(x) means sine Integral of x.
which you can evaluate easily in MATLAB.
Jonathan Sullivan
le 29 Fév 2012
x.*(asin((x-1)./x)-sqrt(2*x-1)./x^2))
1 commentaire
Amir
le 29 Fév 2012
UJJWAL
le 29 Fév 2012
0 votes
Hi Amir ,
To solve the integral of a sin(1-1/x), follow the following steps,
a) Expand sin(1-1/x) and then integrate. b) You wil encounter the integral of sin(1/x) and cos(1/x). For solving cos(1/x) use the integration by parts by taking cos(1/x) as the first function and 1 as the second function. You will in process get expressions for Sin Integral, which is evaluated numerically.
In the same way you can solve for cos(1/x) also Finally rearrange the terms and you will get the answer I have given you . :-)
Hope this helps
Happy to help
UJJWAL
Catégories
En savoir plus sur Numerical Integration and Differentiation dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!