Replace efficiently values in matrix without for-loops

Hi, This is my problem. Suppose you have a vector b:

b=[234 786 674 23];% the values are chosen at random for this example

and a matrix A:

A=[2 1;
   4 4];  %the value of the elements of A should be <=length(b)

it exists a method or a function to obtain a second matrix B of the same dimensions of A but with the values replaced by the corresponding value in b?? For the previous example:

B=[786 234;
    23  23]; % i.e., B(i,j)=b(A(i,j))

this is easily to do with at least one for-loop. but I am looking for a function or method that does this without for loops, maybe in a vectorized way (thus in an efficient way)!

Can someone help me??

Thank you,

Matteo

Answer 1

[Matteo]

ok sorry, it was a stupid question.

I hadn't noticed that b(A) does exactly what I wanted :)

Hope anyway this could be useful for other people.

Bye, Matteo

Answer 2

[the cyclist]

Simple and elegant:

b(A)

Answer 3

[Jonathan Sullivan]

B = b(A);