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How a generate random numbers within a probabilistic range?

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Nikolas Spiliopoulos
Nikolas Spiliopoulos le 3 Nov 2016
Hi there,
I would like to generate random numbers for an input of 48 variables within a probabilistic range. I managed to get results for a particular range (lets say -0.02 +0.02), using rand function. However how can I do the same for a probabilistic range like this:
50% probability the range to be -0.01 +0.01, 30% probability the range to be -0.02 +0.02 and so on.
many thanks
Nikolas
  2 commentaires
Torsten
Torsten le 3 Nov 2016
How can the probability become smaller for a wider range ?
Best wishes
Torsten.
Nikolas Spiliopoulos
Nikolas Spiliopoulos le 3 Nov 2016
Hi again,
thanks for the prompt reply.
Well it has to do with the problem, it's more likely the values to change within a range of -0.01 to +0.01 rather than a range of -0.02 +0.02.
hope that helps
Nikolas

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Réponses (1)

Adam
Adam le 3 Nov 2016
Modifié(e) : Adam le 3 Nov 2016
You could just do a simple 2 layer approach if rand gives you an acceptable distribution within each of your ranges.
e.g.
ranges = [-0.01 0.01; -0.02 0.02; -0.05 0.05];
rangeProbabilities = [0.5 0.3 0.2];
rangeVal = rand( )
rangeIdx = find( cumsum( rangeProbabilities ) >= rangeVal , 1 )
n = 48;
randomNumbers = ( rand( n, 1 ) -0.5 ) * 2 * ranges( rangeIdx, 2 ); % Produce n random numbers in range
Note that last line assumes your ranges are symmetric (in which case there's no point storing the 1st column anyway). If not then it is still simple enough to ensure a random number falls within a single predefined range.
  1 commentaire
Nikolas Spiliopoulos
Nikolas Spiliopoulos le 3 Nov 2016
ok, I"ll give it a try Adam,
thank you so much
regards
Nikolas

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