How to remove MSB bit from a binary number?

suppose i have an cell array 'c' of 1*256 size.

let c(1)=10010000

i want

p1= 10010000;
p2=0010000;
p3=010000;
p4=10000;
p5=0000;
p6=000;
p7=00;
p8=0;

it means in each step the MSB should be removed.. Thank you..plz any body suggest...

[Walter Roberson]

What is the the data type?

[aditya kumar sahu]

it is actually uint8 .but i have converted it into char..so we can do in both ways

Answer 1

[Walter Roberson]

   cellfun(@(b) arrayfun(@(idx) b(idx:end), 1:length(b), 'uniform', 0), c, 'uniform', 0)

[Walter Roberson]

For the uint8 case:

cellfun(@(b)  mod(b, 2.^(8:1)-1), c, 'uniform', 0)

[Guillaume]

For the uint8 case, I'd use:

cellfun(@(b) bitshift(b, -(1:8)), c, 'UniformOutput', false);

There are plenty of functions in matlab to manipulate bits of numbers.

[aditya kumar sahu]

>> a=imread('f.jpg');
>> b=imresize(a,[16 16]);
>> d = cellstr(dec2bin(b,8))';
>> for i = 1 : rows
  for j = 1 : columns

suppose d{i,j}==11000001

i want d{i,j} should be decreased to 7 bit next 6 bit next 5 bit upto 2 bit.i.e. d(i,j)=1000001; d(i,j)=000001; d(i,j)=00001; d(i,j)=0001; d(i,j)=001;d(i,j)=01;..i.e at each step msb bits should be removed.

[Walter Roberson]

That is what my first code does provided you start with cell array of string

Answer 2

[Guillaume]

b = imresize(imread('f.jpg'), [16 1]);
d = arrayun(@(s) bitshift(b, -s), 1:8, 'UniformOutput', false);

d{1} is all the values of b shifted by 1 bit, d{2} is all the values of b shifted by 2 bits, ... d{8} is all the values of b shifted by 8 bits.

There is absolutely no point in converting numbers in strings of 0 and 1 to manipulate bits Computers are much better at manipulating bits of numbers than they are at manipulating characters of strings.

You can always convert the d{i} to strings if you really wish to.

[aditya kumar sahu]

Thank you to Walter Roberson & Guillaume...i got it...