Effacer les filtres
Effacer les filtres

I have a cell (NewCell {1,1}) with 1 column and many rows, each row has or '0' or []. If its '0', I want to make a comparison; if its the other thing, i want a 'V'.

1 vue (au cours des 30 derniers jours)
teste2 = cell(size(catconsumo));
for k=2:(length(Preos2013S1)-1)
if NewCell{1,1}{k} == '0'
mask = strcmp(catracio1, 'low') & strcmp(catpreco, 'high');
teste2(mask) = {'A'};
mask = strcmp(catracio1, 'medium low') & strcmp(catpreco, 'medium high');
teste2(mask) = {'B'};
mask = strcmp(catracio1, 'medium') & strcmp(catpreco, 'medium');
teste2(mask) = {'C'};
mask = strcmp(catracio1, 'medium high') & strcmp(catpreco, 'medium low');
teste2(mask) = {'D'};
mask = strcmp(catracio1, 'high') & strcmp(catpreco, 'low');
teste2(mask) = {'E'};
elseif NewCell{1,1}{k} ~= '0'
teste2{k}='V';
end
end
However, teste2 results with [] in every row, or one of those letters, but regardless of there is a [] or a '0' in NewCell{1,1}. Its not respecting the 'if' condition. Can somebody help me please?
  1 commentaire
bemin
bemin le 8 Nov 2016
You need to give little more details about your cell, However What I see from your code that you are trying to compare number with a string so you ether use strcmp () or write the if without quotations just like this:-
if NewCell{1,1}{k} == 0
...
...
..
etc.
I hope I can help

Connectez-vous pour commenter.

Réponses (1)

James Tursa
James Tursa le 8 Nov 2016
Modifié(e) : James Tursa le 8 Nov 2016
elseif isempty(NewCell{1,1}{k})
The problem you are having is that the result of NewCell{1,1}{k} ~= '0' is empty in that branch, not true, so you don't get into the elseif block.
Or, if you know for sure that there are only '0' and [] in NewCell{1,1}{k}, you could just turn that entire elseif statement into an else. E.g.,
else
teste2{k}='V';
  1 commentaire
Eduardo Rocha
Eduardo Rocha le 8 Nov 2016
Modifié(e) : Eduardo Rocha le 8 Nov 2016
Actually it seemed to work, but in fact it does not. I forgot to add some information:
When NewCell(1,1){k} is '0' and none of those conditions are satisfied, teste2(k) should be '0'. When NewCell(1,1){k} is [], teste2 should be 'V'.
However, teste2 is being [] for situations in which NewCell(1,1){k} is '0' and sometimes its making the comparison when NewCell(1,1){k} is [], which can't happen.
In teste2, there should only be '0', 'A', 'B', 'C', 'D', 'E' and 'V'

Connectez-vous pour commenter.

Catégories

En savoir plus sur Characters and Strings dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by