how to replace by comparing in a double array.?

        I have 4 double matrix, one is c(i,j) of size 256*8,having only 0 and 1 as its elements and z=[0 1 1 1 1 1 1 1 ] and y=[1 0 0 0 0 0 0 0] and b=[ 0 1 0 1 0 1 0]
i want to compare each row of c with z,y,b with below condition.

if any row of c(i,j) matches with z or y and if b(k)==0 then that row of c(i,j)=z,

otherwise/else

c(i,j) matches with z or y but b(k)==1 then that row of c(i,j)=y, else c(i,j) values remain same

i have written the code as this

[row]=size(c);

[row1]=size(b)

for i=1:row

if c(i,:)== z | c(i,:)==y 

for k=1:row1    

              if b(k)==0
             p(i,:)= z;
           else
              p(i,:)= y;     
    end
      end
  end
  end
i could not find where is the wrong why the matrix p does not have the values required..
Thank you in advance.

[Jan]

Please format your code using the "{} Code" button to present it in a readable form.

When you claim, that the posted code is "wrong", please add the information, why you think so. Currently the users have to guess or spend time to find this out, while you have this information already. Offering all you have to make an answer as easy as possible encourages the forum users to spend their time to assist you.

[KSSV]

How it is different with this?

http://in.mathworks.com/matlabcentral/answers/312280-how-to-compare-2-double-array

[aditya kumar sahu]

if any row of c(i,j) matches with z or y and if b(k)==0 then that row will be c(i,j)=z,

otherwise/else

c(i,j) matches with z or y but b(k)==1 then that row will be c(i,j)=y, else c(i,j) values remain same

Answer 1

[Jan]

A bold guess:

[row]=size(c)
for i=1:row
  ...

Note that row is a vector and the expression 1:row does most likely not do, what you expect. Try:

row = size(c, 2);  % Or: numel(c)
for i = 1:row

Do you know and use the debugger? You can set breakpoint in lines and step through the code line by line. This helps to find such problems and it is much more efficient than asking the forum.

[aditya kumar sahu]

if any row of c(i,j) matches with z or y and if b(k)==0 then that row will be c(i,j)=z,

otherwise/else

c(i,j) matches with z or y but b(k)==1 then that row will be c(i,j)=y, else c(i,j) values remain same

[Jan]

@aditya: Repeating sentences from the original question does not add any new information.

Did you notice my suggestion:

 When you claim, that the posted code is "wrong", please add the information, why you think so.