Indexing into a multidemesional array using a multidimensional array

5 vues (au cours des 30 derniers jours)
Kevin McAughey
Kevin McAughey le 18 Nov 2016
Commenté : Guillaume le 18 Nov 2016
This question seems similar to a previously answered question, but I'm not sure if the answer there applies to my problem.
I have an array, X, which has dimensions k by m by n and I have another array, Y, with indices for the first dimension k, which has dimensions m by n. I want to create an output matrix of m by n of each value of X in the k dimension where the index in that k dimension corresponds to the value in Y for each value of m and n.
I know that is a bit confusing, but in essence I want to achieve the following code via clever application of indexing, rather than using nested for loops.
m = size(X,2);
n = size(X,3);
for m_count = 1:length(m)
for n_count = 1:length(n)
output(m_count,n_count) = X(Y(m_count,n_count),m_count,n_count)
end
end

Réponse acceptée

Guillaume
Guillaume le 18 Nov 2016
I think it should rather be:
[rows, columns] = ndgrid(1:size(Y, 1), 1:size(Y, 2));
output = X(sub2ind(size(X), Y, rows, columns))
  2 commentaires
Kevin McAughey
Kevin McAughey le 18 Nov 2016
This seems to work perfectly, now I'll just have to look through it so that I can understand why!
Guillaume
Guillaume le 18 Nov 2016
rows and columns are just two matrices corresponding to the row and column indices of the corresponding elements of Y.
sub2ind converts these three coordinate matrices into a single linear index which can be used to index X.

Connectez-vous pour commenter.

Plus de réponses (1)

Jan
Jan le 18 Nov 2016
Modifié(e) : Jan le 18 Nov 2016
Try this:
output = X(sub2ind(size(X), Y(:), 1:size(x,2), 1:size(x,3))
  1 commentaire
Kevin McAughey
Kevin McAughey le 18 Nov 2016
When I tried this it threw the following error:
Error using sub2ind (line 51)
The subscript vectors must all be of the same size.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by