Index exceeds matrix dimensions while using a for loop
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I tried to make a simple program to find a specific set of numbers, but when I run it, it says "Index exceeds matrix dimensions". The line that causes an issue is "if(r(i+1)==2)"
does anyone know what the problem could be? I don't see it. r is a 10000x1 matrix, so I believe the dimensions are alright.
x=0
while (x==0)
n=10000
r = randi([0 9],n,1);
for i=1:n
if(r(i)==1)
if(r(i+1)==2)
if(r(i+2)==3)
if(r(i+3)==4)
if(r(i+4)==5)
if(r(i+5)==6)
if(r(i+6)==7)
if(r(i+7)==8)
if(r(i+8)==9)
display('found')
display(i)
x=1
end
end
end
end
end
end
end
end
end
end
end
0 commentaires
Réponse acceptée
bio lim
le 28 Nov 2016
You defined your variable r as:
n=10000
r = randi([0 9],n,1);
So now, your r is 10000x1 double.
Then you defined a loop
for i=1:n
So i will go from 1 to 10000. What happens when i reaches to, let's say 10000?
if(r(i+1)==2)
The above is asking if the 10001 element of r is equal to 2, but the dimension of your r is 10000x1. Hence the error occurs.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!