# How can I make these separate for loops into a nested for loop together?

1 vue (au cours des 30 derniers jours)
Muhamed Polovina le 8 Déc 2016
Modifié(e) : per isakson le 22 Déc 2016
clc, clear
A = [1:11; 2:12; 3:13; 4:14; 5:15; 6:16; 7:17 ]
[M N] = size(A);
%
for i = 1:M
Ax = [A(i, N - 5 + 1:N) A(i, 1:N - 5)];
Ax(1,(1:5)) = 0;
k(i,:) = Ax;
end
%
for j = 1:N
Ay = [k(1+2:M,j);
k(1:2,j)];
Ay(end-1:end) = 0;
k(:,j) = Ay;
end
This is the output: A is the starting matrix, and k is after everything is shifted over 5 and up 2. But I can't figure out how to do it as a nested for loop together.
A =
1 2 3 4 5 6 7 8 9 10 11
2 3 4 5 6 7 8 9 10 11 12
3 4 5 6 7 8 9 10 11 12 13
4 5 6 7 8 9 10 11 12 13 14
5 6 7 8 9 10 11 12 13 14 15
6 7 8 9 10 11 12 13 14 15 16
7 8 9 10 11 12 13 14 15 16 17
k =
0 0 0 0 0 3 4 5 6 7 8
0 0 0 0 0 4 5 6 7 8 9
0 0 0 0 0 5 6 7 8 9 10
0 0 0 0 0 6 7 8 9 10 11
0 0 0 0 0 7 8 9 10 11 12
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
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### Réponses (2)

Sally Al Khamees le 22 Déc 2016
Try this:
[r,c]=size(A);
k = zeros(r,c);
for i=1:(r-2)
for j = 6:c
k(i,j) = A(i+2,j-5);
end
end
k
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Roger Stafford le 22 Déc 2016
You don’t need for-loops at all.
k = zeros(size(A));
k(1:5,6:11) = A(3:7,1:6);
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