random matrix 6*3 and i want set row according highest total of row set as first than lower
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Pratik Anandpara
le 15 Déc 2016
Commenté : Pratik Anandpara
le 15 Déc 2016
2.00 1.00 6.00 =9
0 8.00 2.00 =10
1.00 2.00 1.00 =4
5.00 0 8.00=13
6.00 0 5.00=11
3.00 0 6.00=9
now rearrange and set matrix is
5.00 0.00 8.00
6.00 0.00 5.00
0.00 8.00 2.00
2.00 1.00 6.00
3.00 0 6.00
1.00 2.00 1.00
this row order is not fix each time 6*3 random matrix but raw order high is set as first
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KSSV
le 15 Déc 2016
A = [2.00 1.00 6.00
0 8.00 2.00
1.00 2.00 1.00
5.00 0 8.00
6.00 0 5.00
3.00 0 6.00];
thesum = sum(A,2) ;
[val,idx] = sort(thesum,'descend') ;
B = A(idx,:)
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Jos (10584)
le 15 Déc 2016
Let A be your matrix of values:
rowsumA = sum(A,2) % sum over rows
[~,ix] = sort(rowsumA, 'descend') % sort these sums in descending order
B = A(ix,:) sort the matrix A accordingly
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