I have a matrix A and I generate B=randi([0,1],7,3).I want C=A*B only if sum of each row of B=1..I tried this..
A=[1 0 0 1 0 1 1
0 1 1 1 0 0 1
1 0 0 1 1 0 0
1 0 0 0 1 0 1
1 1 0 0 0 1 0
0 1 0 0 0 1 1]
for k=1:numIterations
B=randi([0,1],7,3);
if sum(B,2)==1;
C=A*B;
end
end
how to use IF condition in this case?

2 commentaires

Walter Roberson
Walter Roberson le 19 Déc 2016
What do you want to have happen if the condition is met multiple times within the "for k" loop? You are overwriting all of C each time.
summyia qamar
summyia qamar le 19 Déc 2016
thankyou..I skipped C(k)

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 Réponse acceptée

Roger Stafford
Roger Stafford le 19 Déc 2016

0 votes

if all(sum(B,2)==1)

1 commentaire

I tried this.
A=[1 0 0 1 0 1 1
0 1 1 1 0 0 1
1 0 0 1 1 0 0
1 0 0 0 1 0 1
1 1 0 0 0 1 0
0 1 0 0 0 1 1];
for k=1:numIterations
B=randi([0,1],7,3);
if all(sum(B,2)==1)
C=A*B
end
end
[B C(ones(7,1))]
and result is C =
1 2 1
0 4 0
2 1 0
2 1 0
1 1 1
0 2 1
ans =
0 0 1 1
1 0 0 1
1 0 1 1
1 1 0 1
1 0 1 1
1 0 0 1
0 0 1 1
row 3 is not upto the condition

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Plus de réponses (1)

Steven Lord
Steven Lord le 19 Déc 2016

0 votes

Don't generate B randomly, or at least not the way you're generating it. Your constraint on B is that each row must have exactly one nonzero value. So generate the index of the column in each row that contains the nonzero value and use that to generate a B matrix that is guaranteed to satisfy your constraint.
numRows = 10;
numCols = 5;
rowind = (1:numRows).';
colind = randi(numCols, numRows, 1);
B = accumarray([rowind, colind], 1, [numRows, numCols]);
check = all(sum(B, 2) == 1)
The sz input to accumarray is necessary for the (unlikely) case where no row has a 1 in the last column, to ensure B is the correct size.

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