Precise conversions from double to symbolic
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I have the following number
r = 1.78503
I want to obtain the exact symbolic representation of 1/r, and I applied
p = 1/sym(r);
which gives me 1125899906842624/2009765110711289.
However, if I apply the form sym(1/r) then I got 2522982598259131/4503599627370496 which is different from the previous one. I understand this is due to the floating point numeric 1/r so the later form may not be accurate. Based on this observation, what measures should be taken in order to have exact values in a situation like this ? Is the form 1/sym(r) fully able to extract the exact symbolic representation here ? Thanks.
3 commentaires
James Tursa
le 20 Déc 2016
Modifié(e) : James Tursa
le 20 Déc 2016
Can you clarify this post?
In the first place, 2.1234 cannot be represented exactly in IEEE double:
>> r = 2.1234
r =
2.1234
>> num2strexact(r)
ans =
2.123400000000000176214598468504846096038818359375
So when you do this:
>> r = 2.1234
r =
2.1234
>> sym(r)
ans =
10617/5000
MATLAB is actually making some assumptions behind the scenes that you really meant the exact decimal value 2.1234 to be converted and not the actual number that is present in the IEEE double value.
E.g., the trailing bits have to be different from the closest representation of 2.1234 by 7 bits before this assumption is tossed and an exact conversion of the exact bit pattern is calculated:
>> sym(r+2^6*eps(r))
ans =
10617/5000
>> sym(r+2^7*eps(r))
ans =
597683965547423/281474976710656
And, as you can see, I am getting different numbers than you are showing above for the conversions. The numbers you are showing give:
>> 1125899906842624/2009765110711289
ans =
0.5602
>> 1/ans
ans =
1.7850
>> 2522982598259131/4503599627370496
ans =
0.5602
>> 1/ans
ans =
1.7850
So, what are you really working with here? And why do you need "exact" conversions? What do you mean by "exact"? What are you doing with this downstream?
Walter Roberson
le 20 Déc 2016
Modifié(e) : Walter Roberson
le 20 Déc 2016
Change the assignment in the code I showed, and run the steps, and pick the version that you want. 2522982598259131/4503599627370496 or 1125899906842624/2009765110711289 or 100000/178503 or 560214674263177649675355596264489/1000000000000000000000000000000000 (the last would change if you changed the number of digits you have set.)
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Plus de réponses (2)
John D'Errico
le 21 Déc 2016
Too late of course. But the point is that when you create r as a double:
r = 1.78503;
Then it is NOT stored exactly, as 1.78503. Nothing you do will then allow MATLAB to know that you really intended 1.78503, and not the number actually stored, which is...
sprintf('%0.55f',1.78503)
ans =
1.7850299999999998945554580132011324167251586914062500000
Even if you try to pass that number into sym, MATLAB will get it wrong, because you passed in a double precision number as far as sym was concerned.
vpa(sym(1.78503),55)
ans =
1.78502999999999989455545801320113241672515869140625
A simple solution is to go directly to symbolic form, but even there one must be careful.
r = sym('1.78503')
r =
1.78503
vpa(r,55)
ans =
1.785029999999999999999999999999999999999842248658119649
So it looks like r only had about 40 decimal digits stored. (As a guess, roughly 128 bits in the mantissa.) Still better than 16 digits though.
You can do better, by avoiding decimals completely. Integers work best.
r = sym('178503/100000')
r =
178503/100000
vpa(r,300)
ans =
1.78503
Or, you can use my HPF toolbox.
hpf('1.78503',100)
ans =
1.78503
1 commentaire
James Tursa
le 21 Déc 2016
OP still hasn't stated why there is a need for "exact" conversions and what they are being used for downstream. So I have yet to be convinced that this all isn't just a pointless exercise ...
Karan Gill
le 9 Jan 2017
Use quotes to keep your input exactly as it.
r = sym('1.78503')
But you don't get the fractional representation since you asked to keep it exactly as the decimal.
>> p = 1/r
p =
0.56021467426317764967535559626449
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