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Distances along a plotted line?

15 vues (au cours des 30 derniers jours)
Keith Lewis
Keith Lewis le 23 Déc 2016
Commenté : Keith Lewis le 5 Jan 2017
I have x and y matrices with y representing elevations at points x.
For instance
x = [0 5 10]
y = [2 4 1]
plot(x,y) gives me a cross section of elevations.
I want to mark various distances along the plotted line. For instance, place a marker every 1m along the line, or put individual markers at specific distances along the line.
How can I do this?
Thanks!

Réponse acceptée

Walter Roberson
Walter Roberson le 23 Déc 2016
marker_dist = 1;
x = [0 5 10];
y = [2 4 1];
dist_from_start = cumsum( [0, sqrt((x(2:end)-x(1:end-1)).^2 + (y(2:end)-y(1:end-1)).^2)] );
marker_locs = marker_dist : marker_dist : dist_from_start(end); %replace with specific distances if desired
marker_indices = interp1( dist_from_start, 1 : length(dist_from_start), marker_locs);
marker_base_pos = floor(marker_indices);
weight_second = marker_indices - marker_base_pos;
marker_x = x(marker_base_pos) .* (1-weight_second) + x(marker_base_pos+1) .* weight_second;
marker_y = y(marker_base_pos) .* (1-weight_second) + y(marker_base_pos+1) .* weight_second;
plot(x, y);
hold on;
plot(marker_x, marker_y, 'r+');
hold off
  2 commentaires
Keith Lewis
Keith Lewis le 5 Jan 2017
Awesome thank you, this is great!

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Plus de réponses (2)

Roger Stafford
Roger Stafford le 23 Déc 2016
Modifié(e) : Roger Stafford le 23 Déc 2016
The approximate arclength along your curve from (x(i1),y(i1)) to (x(i2),y(i2)) can be computed as the sum of the line segment lengths connecting successive points between the two end points:
n = i2-i1;
s = sum(sqrt((x(i1+(1:n))-x(i1+(0:n-1))).^2-(y(i1+(1:n))-y(i1+(0:n-1))).^2));

Image Analyst
Image Analyst le 23 Déc 2016
For straight lines it's pretty trivial. For more general curves, see John D'Errico's interparc(): http://www.mathworks.com/matlabcentral/fileexchange/34874-interparc
Description
A common request is to interpolate a set of points at fixed distances along some curve in space (2 or more dimensions.) The user typically has a set of points along a curve, some of which are closely spaced, others not so close, and they wish to create a new set which is uniformly spaced along the same curve.
When the interpolation is assumed to be piecewise linear, this is easy. However, if the curve is to be a spline, perhaps interpolated as a function of chordal arclength between the points, this gets a bit more difficult. A nice trick is to formulate the problem in terms of differential equations that describe the path along the curve. Then the interpolation can be done using an ODE solver.
As an example of use, I'll pick a random set of points around a circle in the plane, then generate a new set of points that are equally spaced in terms of arc length along the curve, so around the perimeter of the circle.

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