str2double breaks when you pass in a vector?

this works:

double = str2double('06012015');

but this doesn't:

doubles = str2double(['06012015' '06022015']);

whos doubles gives me this:

-------

6.0120e+14

Name         Size            Bytes  Class     Attributes

doubles      1x1                 8  double  
-------

[Jan]

['06012015' '06022015'] is the same as '0601201506022015' .

Answer 1

[KSSV]

str1 = str2double([{'106012015'}  {'06022015'}])

str2 = str2num(['06012015' ;'06022015'])

[59morgan]

thanks for your help

what I really want to do is this:

%start with a date times vector

datetimes = [datetime('06/01/2015') ; datetime('06/02/2015')];

%now remove any kind of punctuation, we just want digits

date_strings = datestr(datetimes, 'mmddyyyy');

%now convert those char arrays to doubles? docs say you can pass in a char array vector...

doubles = str2double(date_strings);

%problem: the date strings get concatenated and it doesn't work

[Walter Roberson]

str2double( cellstr(date_strings) )

Answer 2

[Sean de Wolski]

In >=R2016b, you can just call double on the string directly:

double(string({'06012015' '06022015'}))