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is it possible to do something like this in the loop:
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if true
% load Time;
Time_test_1 = Time;
clear Time;
%load Time again;
Time_test_2 = Time;
clear Time;
%load time again;
Time_test_3 = Time;
clear Time;
end
1 commentaire
Stephen23
le 13 Jan 2017
It is possible, but it is a really really bad idea. It is a very bad habit to learn. Naming variables in a loop makes your code slow, buggy, hard to debug, and harder to understand. Read this to know why:
Learn to use indexing rather than make lots of separate variables. Then your life suddenly gets better :)
Réponses (1)
the cyclist
le 13 Jan 2017
Modifié(e) : the cyclist
le 13 Jan 2017
if true
% load Time;
Time_test{1} = Time;
clear Time;
%load Time again;
Time_test{2} = Time;
clear Time;
%load time again;
Time_test{3} = Time;
clear Time;
end
which can easily be looped over ...
for ii = 1:3
% load Time
Time_test{ii} = Time;
clear Time
end
This forum has hundreds of posts about why that is a better way to code.
3 commentaires
Guillaume
le 13 Jan 2017
So? You can have cell arrays of cell arrays.
If the cell arrays all have the same number of rows or columns, you could also concatenate them.
Note that I would avoid using load without an output. Rather than:
load('somefile'); %pops the Time variable into existence.
Time_test{idx} = Time;
Use filecontent = load('somefile'); Time_test{idx} = filecontent.Time;
There's no danger of unknowingly overwriting existing variables with the second method.
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