How can I create overlapping subvectors?

For example I have a data set that has 12 elements as a vector.

x = [1;2;3;4;5;6;7;8;9;10;11;12]

I use reshape to create subvectors that split the data up as new vectors organized in an array.

array = reshape(x,4,[]);

Which gives me a way to get these vectors. So my new vectors are.

x1 = [1;2;3;4]

x2 = [5;6;7;8]

x3 = [9;10;11;12]

My question is there command that lets me get the new vectors as overlays or overlapping sections? Do I have to custom program this?

x1 = [1;2;3;4]

x2 = [3;4;5;6]

x3 = [5;6;7;8]

x4 = [7;8;9;10]

x5 = [9;10;11;12]

Answer 1

[Jan]

x = [1;2;3;4;5;6;7;8;9;10;11;12];
y = buffer(x, 4, 2);

>> y = 
   0     1     3     5     7     9
   0     2     4     6     8    10
   1     3     5     7     9    11
   2     4     6     8    10    12

y = y(:, 2:end);

I assume, "x1, x2, ..." means "x(1, :), x(2, :), ...". Assigning different variables would be a bad idea.

Answer 2

[Andrei Bobrov]

out = x(bsxfun(@plus,(1:4).',0:2:numel(x)-3))

OR

out = x(cumsum([(1:4).',2*ones(4,(numel(x)-4)/2)],2))

OR

y=buffer(1:numel(x),4,2)
out = x(y(:,all(y)))

Use x1,x2... bad idea, please read here.