How can i solve this equation ?

1 view (last 30 days)
Hi
How ca i solve the attached equation to find lamda ?
When all the other terms are known.

Accepted Answer

Jorge Mario Guerra González
If you want to get multiple answers use vpasolve function. Set the number of answers you want yo get and the code will pick some then in a random way.
syms lambda
Mt=1; % The value of your variables
m=1;
L=1;
lt=1;
eqn= 1+(cos(lambda)*cosh(lambda))+((lambda*Mt/(m*L))*(cos(lambda)*sinh(lambda)-sin(lambda)*cosh(lambda)))-((lt*lambda^3)/m*L^3)*(cosh(lambda)*sin(lambda)+sinh(lambda)*cos(lambda))+ ((Mt*lt*lambda^4)/m^2*L^4)*(1-cosh(lambda)*cos(lambda)) ==0;
for n = 1:50
vpasolve(eqn,lambda,'random',true)
end
this example gives you 50 answers. The answer before gives the first it finds.
  3 Comments
Jorge Mario Guerra González
syms lambda
Mt=1; % The value of your variables
m=1;
L=1;
lt=1;
eqn= 1+(cos(lambda)*cosh(lambda))+((lambda*Mt/(m*L))*(cos(lambda)*sinh(lambda)-sin(lambda)*cosh(lambda)))-((lt*lambda^3)/m*L^3)*(cosh(lambda)*sin(lambda)+sinh(lambda)*cos(lambda))+ ((Mt*lt*lambda^4)/m^2*L^4)*(1-cosh(lambda)*cos(lambda)) ==0;
k=zeros(1,50);
for n = 1:50
k(i)=vpasolve(eqn,lambda,'random',true)
end
that should create the vector

Sign in to comment.

More Answers (1)

Jorge Mario Guerra González
Just use the function solve, which uses numerical techniques to find variables.
try this.
syms lambda
Mt=1; % The value of your variables
m=1;
L=1;
lt=1;
%check if I wrote this correctly
eqn= 1+(cos(lambda)*cosh(lambda))+((lambda*Mt/(m*L))*(cos(lambda)*sinh(lambda)-sin(lambda)*cosh(lambda)))-((lt*lambda^3)/m*L^3)*(cosh(lambda)*sin(lambda)+sinh(lambda)*cos(lambda))+ ((Mt*lt*lambda^4)/m^2*L^4)*(1-cosh(lambda)*cos(lambda)) ==0;
value=solve(eqn,lambda) %solution for lamda
  2 Comments
John D'Errico
John D'Errico on 19 Jan 2017
You cannot find an infinite number of solutions. If you tried to write them all down, it would take infinitely long.

Sign in to comment.

Categories

Find more on Mathematics in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by