error using squeeze function

i have values as

A(:,:,1)=
 1   3  4 
 .2 .3 .9  
;
;
;
A(:,:,56)=
 10   13  9 
  1   2   20

i need to display as

A=
1   3    4 
.2 .3 .9
;
;
10   13  9 
1   2   20  

i tried squeeze,but did not get exact answer,please help

[Jan]

Does "did not get the exact answer" means, that the answer is :_completely_ wrong - or only _partially_ wrong?!

I do not understand the notation with the semicolons. Please post what you try and how you insert the semicolons into the output.

[Daniel Shub]

How exactly do you expect to represent a 3D matrix in 2D?

Answer 1

[Jan]

Perhaps:

reshape(permute(A, [3,1,2]), 4, 3)

?

[EDITED] No, the above is not correct. Better:

reshape(permute(A, [1,3,2]), [], 3)

[Walter Roberson]

I think your reshape is wrong there. The original matrix size goes to at least 56 in the third dimension, so you are not going to fit the matrix in to a 4 x 3 .

[Jan]

Thanks Walter. Now I get an idea what the semicolons should mean.

Answer 2

[Walter Roberson]

squeeze() is only for eliminating singular dimensions, such as for transforming a 17 x 1 x 43 array in to a 17 x 43 array.

You do not have any singular dimensions, so squeeze() is not going to help you.

[kash]

So walter how to process it ,please help

[Walter Roberson]

It'd probably take a permute() and reshape() and possibly a transpose after.