delete rows from cell array

i have a cell array with string as below (format is "number""space""-""space""number")

1234 - 5678
543 - 2345
5678 - 1234

delete the numbers relations such as

1234 - 5678
5678 - 1234

and keep first one of them and get output as

1234 - 5678
543 - 2345

i need to search using '-'

i get empty matrix, when i do as below

index = find(ismember(cellArr(1), ' - '))

[Rik]

So your question is how to remove the rows with pairs that are descending?

index is empty, because you are comparing a single cell with the text ' - '. I think you should take a look at strfind.

[Adam]

You say you want to delete numbers, but then give an example output which still contains the same first line as I thought you wanted to delete?

Answer 1

[Guillaume]

I'm assuming that you want to delete repeated pairs regardless of the order the numbers appear in the pair.

Possibly the easiest way would be:

c = {'1234 - 5678';
    '543 - 2345';
    '5678 - 1234';}
[~, urows] = unique(regexprep(c, '([^- ]*) - ([^-]*)', '${strjoin(sort({$1, $2}), '' - '')}'), 'stable');
filteredc = c(urows)

Answer 2

[Pooja Patel]

A(1:2)={rand(10,6)}

A =

      [10x6 double]    [10x6 double]

>> row=2; A{1}(2,:)=[] %delete 1 row from 1 cell

A =

      [9x6 double]    [10x6 double]