how i can vectorize this code using bsxfun or meshgrid?

Hi,
I am trying to vectorize this code, but I dont know how to start it, I read the help files for both bsxfun and meshgrid but no luck. Can someone please guide how to look at this rather than giving the code. My code is working for me but i want to improve it.
s1= 50;
s2=100;
E_=zeros(s2,s2);
grid_=linspace(-2.5,2.5,s2);
tau=linspace(-pi,pi,s1);
x=cos(tau);
y=sin(tau);
cur=myfun(x,y); %returns vector
for k=1:s2
for m=1:s2
for n=1:s1
R= abs(sqrt((grid_(m)-x(n))^2+(grid_(k)-y(n))^2));
u_(n)= besselj(0,R)*cur(n);
end
E_(k,m)=abs(trapz(tau,u_));
end
end
Thanks
Turker

 Réponse acceptée

Jan
Jan le 14 Mar 2017
Modifié(e) : Jan le 15 Mar 2017
You can replace the inner loop by:
R = abs(sqrt((grid_(m)-x) .^ 2 + (grid_(k)-y) .^ 2)); % [EDITED]: ^ to .^
u_ = besselj(0, R) .* cur;
I guess, that the abs() is not required.

4 commentaires

Thanks Jan, x and y are array. And I a calculating the distance between points one by one. When we change it like this, does R become an array?
Jan
Jan le 15 Mar 2017
Modifié(e) : Jan le 15 Mar 2017
Yes, R has the same size as x and y, and u_ has also. At least if you run the improved version which uses the elementwise squaring .^2. See [EDITED]
Hi Jan, it returns error as;
Assignment has more non-singleton rhs dimensions than
non-singleton subscripts
Error in testfields (line 121)
E_(k,m)=abs(trapz(tau,u_));
ttopal
ttopal le 16 Mar 2017
Modifié(e) : ttopal le 16 Mar 2017
R = abs(sqrt((grid_(m)-x) .^ 2 + (grid_(k)-y) .^ 2))'; %transpoze added.
u_ = besselj(0, R) .* cur;
Now it works! Thank you Jan!

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