financial time series obiect: get a column by name string?

Say, I have a fts object of type:
dt =
desc: (none)
freq: Daily (1)
'dates: (2715)' 'times: (2715)' 'A: (2715)' 'B: (2715)' 'C: (2715)'
to access a column, you'd do something like:
dt.A
What if you'd want to place this in a function and pass the column name as a string argument:
col_name = 'A'
Is there a way to access this column from dt having its name in a string?

 Réponse acceptée

dpb
dpb le 17 Mar 2017
Again, similarly to the other question, relate it to the struct; I didn't find the similar documentation under the financial TS link, but here is link for structures; should work the same way...

1 commentaire

Andy
Andy le 17 Mar 2017
Modifié(e) : Andy le 17 Mar 2017
it works indeed:
dt.Close
cl = 'Close'
dt.(cl)
produce similar results. Thanks!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

Produits

Question posée :

le 17 Mar 2017

Modifié(e) :

le 17 Mar 2017

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by