how can i draw Vector/Direction field for van der pol oscillator ?

3 vues (au cours des 30 derniers jours)
Vennala Anugu
Vennala Anugu le 23 Mar 2017
I am having problem in drawing the vector / direction field for Van der Pol Oscillator which looks something like this https://en.wikipedia.org/wiki/Van_der_Pol_oscillator#/media/File:VanDerPolOscillator.png
i have written this code :
options = odeset('MaxStep',0.5);
temp = inputdlg('Enter mu value');
mu = str2double(temp{1,1});
[t,y] = ode45(@(t,y) vdp1_1(t,y,mu),[0 10],[2; 0],options);
figure(1);
plot(t,y(:,1)),
xlabel('time t');
ylabel('Y1(t)');
title('t vs Y1(t)');
figure(2);
plot(t,y(:,2))
xlabel('time t');
ylabel('Y2(t)');
title('t vs Y2(t)');
figure(3),
plot(y(:,1),y(:,2)) , hold on
quiver(y(:,1), y(:,2), gradient(y(:,1)), gradient(y(:,2) ))
hold off
xlabel('y1(t)');
ylabel('Y2(t)');
title('y1(t) vs Y2(t)');
function dydt = vdp1_1(t,y,mu)
dydt = zeros(2,1);
dydt(1) = y(2);
dydt(2) = [mu * (1-y(1)^2)*y(2)-y(1)];
end
my code doesnot give any errors , and also doesnt give the vector field .It just gives gradient boundary of the ode using quiver for y1 vs y2
Any help would be appreciable!

Réponses (2)

KSSV
KSSV le 23 Mar 2017

Michael Mathew
Michael Mathew le 12 Déc 2018
function VanderPol_plot()
steps = 20;
s1 = linspace(-6,6,steps);
s2 = linspace(-6,6,steps);
% creates two matrices one for all the x-values on the grid, and one for
% all the y-values on the grid.
[x,y] = meshgrid(s1,s2);
u = zeros(size(x));
v = zeros(size(x));
for i=1:numel(x)
[t,y_sol] = ode23(@vdp1,[0 20],[x(i); y(i)]);
figure(1);
plot(y_sol(:,1),y_sol(:,2)); hold on;
figure(2);
quiver(y_sol(:,1), y_sol(:,2), gradient(y_sol(:,1)), gradient(y_sol(:,2) ), 'r'); hold on;
end
figure(1);
ylabel('Solution plot');
figure(2);
title('Gradient plot')
end
function dydt = vdp1(t,y, mu)
%Vandepol oscillator ode
if nargin < 3
mu = 1;
end
dydt = [y(2); (mu-y(1)^2)*y(2)-y(1)];
end

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