Select part of a string

139 vues (au cours des 30 derniers jours)
JE101
JE101 le 23 Mar 2017
Commenté : Gina Eldridge le 4 Avr 2022
I have a large column vector of strings. The strings vary in length. I would like to select out the last 5 characters of the actual string (i.e., I don't want 5 blank spaces that you would get by converting it to a char array and then selecting the last 5 columns).
I have a complicated way of doing this by switching between a string array and a character array and using sub2ind, but I was wondering if there is a simpler way to do this. I've tried using strtok and flip, but can't get it to do exactly what I want.
If possible, I'd like to avoid using a loop (because of the size of the array).
If you use excel, I want to do the equivalent of the RIGHT function.
Any suggestions would be much appreciated! Thanks.

Réponse acceptée

Stephen23
Stephen23 le 23 Mar 2017
Modifié(e) : Stephen23 le 23 Mar 2017
A string array treats each string as being atomic, whereas you need to be able to access each character as atomic. Use cellstr to convert to a cell array of chars, and then use cellfun to extract the parts you need:
cellfun(@(s)s(end-4:end),cellstr(inp),'uni',0)
  1 commentaire
JE101
JE101 le 23 Mar 2017
Perfect! Thanks Stephen.

Connectez-vous pour commenter.

Plus de réponses (1)

Steven Lord
Steven Lord le 23 Mar 2017
Another approach, if you're using the string class introduced in release R2016b, is to use extractAfter.
>> animals = {'cat'; 'elephant'; 'dog'; 'hippopotamus'};
>> animalsString = string(animals);
>> lastTwoLetters = extractAfter(animalsString, strlength(animalsString)-2)
lastTwoLetters =
4×1 string array
"at"
"nt"
"og"
"us"
  2 commentaires
JE101
JE101 le 23 Mar 2017
That's great. Thanks Steven.
Gina Eldridge
Gina Eldridge le 4 Avr 2022
love it

Connectez-vous pour commenter.

Catégories

En savoir plus sur Cell Arrays dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by