How to crop an image into blocks and store blocks in an array or matrix ?

3 vues (au cours des 30 derniers jours)
I need to crop an image into blocks an store the blocks in a matrix because I need to apply BoxCounting algorithm on each block.

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Preda Virgil Ionut
Preda Virgil Ionut le 4 Avr 2017
Modifié(e) : Preda Virgil Ionut le 4 Avr 2017
So, I want to Thank you four your answers.
The BoxCounting Algorithm is this: click
I will be more specific: Step 1: I need to divide a binary picture in blocks Step 2: I need to apply BoxCounting function on each block Step 3: My result need to be a matrix or an array with the values of BoxCounting applied on each block.
If I use:
T=blockproc(Ibw, blockSize, @BoxCountfracDim);
My response from Matlab is a matrix with BoxCounting applied on the full image, not on every block. I hope you understand me.
I am so grateful for your help !
  1 commentaire
Image Analyst
Image Analyst le 4 Avr 2017
I don't understand. blockproc() will take a block of pixels and pass it to your function. In that function you can do whatever you want - Hausdorf box counting or whatever. Then your "answer" for that block is stored as the answer for that particular location of the block, for example the block centered at (13, 450) or wherever it may be. So it does it both on every block, and on the whole image (since it was done on every block in the whole image). If my image was 10 by 20, and my blocksize was 2, and I "jumped" by the blocksize, and I returned a single scalar value for each block location, then at the output of blockproc() I'd have a 5 by 10 image, because five 2x2 blocks could fit vertically and 10 2x2 blocks could fit horizontally.

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Plus de réponses (5)

mizuki
mizuki le 26 Mar 2017
Create a function cropAndSaveBlock.m first, which is specified in the function of blockproc. This function writes the cropped images with imwrite .
function cropAndSaveBlock(bs)
save_loc = pwd;
fileName = [save_loc, '\img', int2str(bs.location(1)), '_', int2str(bs.location(2)), '.jpg'];
imwrite(bs.data, fileName)
end
Call this function from blockproc .
After reading an image with imread, set the cropped image size. The third input argument is cropAndSaveBlock.m - the function that you want to apply to the image.
>> I = imread('peppers.png');
>> blockSize = [200 200];
>> blockproc(I, blockSize, @cropAndSaveBlock);

Image Analyst
Image Analyst le 1 Avr 2017
I don't know what that algorithm is, but see the FAQ http://matlab.wikia.com/wiki/FAQ#How_do_I_split_an_image_into_non-overlapping_blocks.3F or else use nlfilter() or blockproc() (demos attached).

Preda Virgil Ionut
Preda Virgil Ionut le 27 Mar 2017
Modifié(e) : Preda Virgil Ionut le 27 Mar 2017
Thank you very much. When I run the code It doesn't return me the matrix with the stored blocks, the answer is:
Ans =
[]
How can I acces the matrix with the stored blocks ?
  1 commentaire
mizuki
mizuki le 27 Mar 2017
You need to make a folder called 'img' first to the current folder (pwd) by
>> mkdir('img')
Then, run the code again. .jpg file is stored under that img folder. Load those images by
>> I = imread('*filename*.jpg')

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Preda Virgil Ionut
Preda Virgil Ionut le 1 Avr 2017
Modifié(e) : Preda Virgil Ionut le 1 Avr 2017
Thank you again, your code is cropping the image into blocks stored in "img" folder. But how can I apply BoxCounting algorithm on each block? My result need to be an array or a matrix with the BoxCounting values of each block.
The result is:
Ans =
[ ]

Preda Virgil Ionut
Preda Virgil Ionut le 4 Avr 2017
It is okey now, thank you very much ! Problem solved.
  2 commentaires
M Sh
M Sh le 20 Oct 2019
please help me and tell me how the problem was solved?
Image Analyst
Image Analyst le 20 Oct 2019
I bet he used either blockproc() or mat2cell() like the FAQ said. The link is in my answer.

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