for loop

2 vues (au cours des 30 derniers jours)
Ferd
Ferd le 23 Mar 2012
Hey
I have 2 matrices, A and B, of same length and I have to create another variable C
A = goes from minimum to maximum to minimum (Fuel quantity)
B = contains prezeros and the remainder has some values
For example,
A = [1;2;3;4;5;6;7;8;9;10;9;8;7;6;5;4;3;2;1;0.5];
B = [0;0;0;0;0;0;0;0;0;0;0;0;5;7;3;2;0;0;0;0];
C = [A(1);A(2);A(3);A(4);A(5);A(6);A(7);A(8);A(9);A(10);A(11);A(12);A(13);A(14)-B(13);A(15)-B(14);A(16)-B(15);A(17)-B(16);A(18);A(19);A(20)];
The only limitation is that the value of A and B values are tacked on in the array after every iteration. What I have done so far is
C(1) = A(1);
C_difference(1) = A(2) – B(1);
But I am not sure when do you invoke the subtraction cause each time the values are tacked on in the respective array.
Thanks
Ferd
  3 commentaires
Thomas
Thomas le 23 Mar 2012
Are you finding the difference between the A and B vectors.
You do not need a loop if that is what you want.. MATLAB can perform element wise subtraction without loops.
Ferd
Ferd le 23 Mar 2012
Hey Guys,
Affirmative, however, I was pondering on it for a while now, setting 0 as the first value of a New B array and then tacking on its next value (based on A and B) and then followed by simply C = A(:,1) - NewB(:,1) within the loop should work (i think). Because it's taking the updated value of A and subtracted from the previous iteration step value of B. Adding a zero would, i believe, work.
Technically, I need to find the difference between that A and the previous value B from that row onwards when B has non-zero values. Otherwise, the C is just the A values.
Thanks

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