Integration In Matlab
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Thanks to andrei bobrov for your answer! Yes R1=R2. Your coding seems to work, but the value(answer) is a huge one to know the exact value. Can we command in MATLAB to give the calculated result only upto 4 decimal place.
syms r R1=sqrt(3)*(2*r.^2-1) R2=sqrt(3)*(2*r.^2-1) b = .7; S=2*pi*imag(int(exp(1i*b*R1)*r,r,0,1)*int(R2*exp(-1i*b*R1)*r,r,0,1)) out = vpa(S);
2 commentaires
Alexander
le 23 Mar 2012
Also, if something works for you, could you please accept the answer? So others know that the matter is resolved.
Réponse acceptée
Alexander
le 23 Mar 2012
Just use double:
syms r
R1=sqrt(3)*(2*r.^2-1)
R2=sqrt(3)*(2*r.^2-1)
b = .7;
S=2*pi*imag(int(exp(1i*b*R1)*r,r,0,1)*int(R2*exp(-1i*b*R1)*r,r,0,1))
out = vpa(S);
double(out)
ans =
-0.7308
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