Effacer les filtres
Effacer les filtres

Finding row indexes in array

3 vues (au cours des 30 derniers jours)
lucksBi
lucksBi le 4 Avr 2017
Commenté : lucksBi le 17 Avr 2017
I have an array
a=[0 0 1 0 ; 1 2 3 0; 1 0 3 4; 0 2 0 0 ]
& cell array like
b{1,1}=[4;3]
b{2,1}=[3;1;4]
I want to find elements of cell array in a. For example: for b{2,1} 1st, 3rd and 4th row of a should be displayed and 2nd should be zero.
Thanks in advance

Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 4 Avr 2017
a=[0 0 1 0 ; 1 2 3 0; 1 0 3 4; 0 2 0 0 ];
b{1,1}=[4;3];
b{2,1}=[3;1;4];
v = 1:size(a,1);
t = cell2mat(cellfun(@(x)ismember(v,x),b,'un',0))';
out = a.*permute(t,[1,3,2]);
  7 commentaires
lucksBi
lucksBi le 5 Avr 2017
here are .mat files of a & b matrices
lucksBi
lucksBi le 17 Avr 2017
hey can you please help on this matter? i am unable to fix this issue with with given mat files.

Connectez-vous pour commenter.

Plus de réponses (1)

Thorsten
Thorsten le 4 Avr 2017
idx = cellfun(@(x) any(ismember(a, x)), b, 'UniformOutput', false);
rows = cellfun(@(x) a(:, x), idx, 'UniformOutput', false);
Or in one line:
rows = cellfun(@(x) a(:, any(ismember(a, x))), b, 'UniformOutput', false);
  3 commentaires
Thorsten
Thorsten le 4 Avr 2017
Like this?
idx = cellfun(@(x) any(ismember(a, x)), b, 'UniformOutput', false);
a0 = zeros(size(a));
for i = 1:numel(idx)
rows{i} = a0;
rows{i}(:,idx{i}) = a(:,idx{i});
end
lucksBi
lucksBi le 4 Avr 2017
result should be like: result{1,1}= [0,0,0,0;0,0,0,0;1,0,3,4;0,2,0,0] result{1,2}= [0,0,1,0;0,0,0,0;1,0,3,4;0,2,0,0]

Connectez-vous pour commenter.

Catégories

En savoir plus sur Matrices and Arrays dans Help Center et File Exchange

Tags

Aucun tag saisi pour le moment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by