There is a bug with the griddedInterpolant function with nearest and linear methods. If the query set contains any out-of-range values, the entire evaluated set is NaN, not just the results corresponding to the out-of-range queries.
In contrast, the griddedInterpolant with cubic interpolation method returns NaN for only out-of-range queries and correctly evaluates the in-range queries.
This is an problem for me because I'd like to use the linear method. I'm currently filtering out the out-of-range values from the query before processing, but the best solution would be to get the linear griddedInterpolant to work as it should. How should I fix it?
This bug is demonstrated by the following example script:
[X,Y,Z] = ndgrid(1:10,1:10,1:10);
V = X.^.5 + Y.^.5 + Z.^.5;
nearestInterp = griddedInterpolant(X,Y,Z,V,'nearest');
linearInterp = griddedInterpolant(X,Y,Z,V,'linear');
cubicInterp = griddedInterpolant(X,Y,Z,V,'cubic');
splineInterp = griddedInterpolant(X,Y,Z,V,'spline');
[Xq,Yq,Zq] = ndgrid(0:.5:10,0:.5:10,0:.5:10);
Vq_nearest = nearestInterp(Xq,Yq,Zq);
Vq_linear = linearInterp(Xq,Yq,Zq);
Vq_cubic = cubicInterp(Xq,Yq,Zq);
Vq_spline = splineInterp(Xq,Yq,Zq);
Thanks, Nick

3 commentaires

Honglei Chen
Honglei Chen le 26 Mar 2012
Hi Nick, which version of MATLAB are you using, I tried this in R2012a and couldn't reproduce it.
Marc Lalancette
Marc Lalancette le 18 Oct 2012
I know this is an old thread but I also ran into this problem, using version 2011b. Is it possible to get this fixed without paying hundreds of dollars for a new version?
Matt J
Matt J le 18 Oct 2012
Modifié(e) : Matt J le 18 Oct 2012
The best solution, other than upgrading, is probably to create your own wrapper that separates out-of-bounds values from inbound values and only calls griddedInterpolant on the latter. You would do that only when the linear interpolation method is active, of course.

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 Réponse acceptée

Sean de Wolski
Sean de Wolski le 18 Oct 2012

0 votes

This behavior was fixed in R2012a. If you are current on SMS, you can download R2012a or R2012b for free.

5 commentaires

Wen
Wen le 28 Mai 2014
I'm seeing the same problem for spline in R2014a.
Sean de Wolski
Sean de Wolski le 28 Mai 2014
Wen, can you provide a minimal working example?
Wen
Wen le 1 Juin 2014
Sorry, I realized the problem I found was a bit different then the topic question. It has to do with ignoring NaN values in V when making the interpolated surface. If nearest, linear, or cubic are used, I can get the values of the interpolated surface as long as it's not close to the x, y, z values at which V is NaN. However, the spline option makes everything NaN instead of only at those x, y, z values.
I added one line to the one Nick gave:
[X,Y,Z] = ndgrid(1:10,1:10,1:10);
V = X.^.5 + Y.^.5 + Z.^.5;
V(10, 10, 10) = NaN;
nearestInterp = griddedInterpolant(X,Y,Z,V,'nearest');
linearInterp = griddedInterpolant(X,Y,Z,V,'linear');
cubicInterp = griddedInterpolant(X,Y,Z,V,'cubic');
splineInterp = griddedInterpolant(X,Y,Z,V,'spline');
[Xq,Yq,Zq] = ndgrid(0:.5:10,0:.5:10,0:.5:10);
Vq_nearest = nearestInterp(Xq,Yq,Zq);
Vq_linear = linearInterp(Xq,Yq,Zq);
Vq_cubic = cubicInterp(Xq,Yq,Zq);
Vq_spline = splineInterp(Xq,Yq,Zq);
Matt J
Matt J le 2 Juin 2014
Modifié(e) : Matt J le 2 Juin 2014
That's not a bug, I don't think. With splines, the piecewise polynomial coefficients used to interpolate between the V(i) depend on all V(i) simultaneously. Any NaNs in the given data set can be expected to propagate everywhere.
Wen
Wen le 2 Juin 2014
Ah ok, makes sense. I see cubic has more NaNs in its interpolated values than linear, and it depends on 4 points (or is it 3?) rather than 2. Okay.

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