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For Loops with Increments Less Than One

2 vues (au cours des 30 derniers jours)
cestcandice
cestcandice le 12 Avr 2017
Commenté : cestcandice le 12 Avr 2017
I have to solve this equation with a for loop from 1 to 10 in increments of .01, but what I'm doing isn't working and I don't know why. It works just the way I want to when I take a way the constraint for the increment. Here's what I'm doing:
for t=1:.01:10
x(t)=a*cos((sqrt(g/l))*t)
end

Réponse acceptée

Matt J
Matt J le 12 Avr 2017
t=1:.01:10;
for i=1:length(t)
x(i)=a*cos((sqrt(g/l))*t(i))
end
  2 commentaires
Matt J
Matt J le 12 Avr 2017
Although, this entire loop could be done in one line,
x=a*cos((sqrt(g/l)) * (1:0.01:10) )
cestcandice
cestcandice le 12 Avr 2017
Oh my gosh! Thank you... I have so much trouble with loops...
Yes, I know it can be done in one line. However, I have to use a for loop.
Thank you!

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