Effacer les filtres
Effacer les filtres

Split array into separate arrays at row with NaNs

19 vues (au cours des 30 derniers jours)
Douglas Anderson
Douglas Anderson le 14 Avr 2017
Commenté : Andrew Sol le 21 Jan 2023
Hello,
Probably a simple problem? I have been sent some data in an Excel file that has several sets of data on one sheet. The data are separated into the individual sets with a blank line, that becomes a row of "NaN"s. How can I make separate arrays from this big one? I didn't see the answer to this in documentation.
Thanks!
Doug Anderson

Réponse acceptée

Stephen23
Stephen23 le 14 Avr 2017
Modifié(e) : Stephen23 le 14 Avr 2017
First lets define some trial data:
>> M = [0,1;2,3;NaN,NaN;4,5;6,7;NaN,NaN;8,9]
M =
0 1
2 3
NaN NaN
4 5
6 7
NaN NaN
8 9
>> idx = all(isnan(M),2);
Method One: accumarray:
>> idy = 1+cumsum(idx);
>> idz = 1:size(M,1);
>> C = accumarray(idy(~idx),idz(~idx),[],@(r){M(r,:)});
>> C{:}
ans =
0 1
2 3
ans =
4 5
6 7
ans =
8 9
Method Two: mat2cell:
>> idr = diff(find([1;diff(idx);1]));
>> D = mat2cell(M,idr(:),size(M,2));
>> D{1:2:end}
ans =
0 1
2 3
ans =
4 5
6 7
ans =
8 9
You can access these data easily and efficiently using cell indexing, e.g.:
>> C{2}
ans =
4 5
6 7
Warning: Whatever you do, do NOT try to create lots of arrays in the workspace. This will be slow, buggy, obfuscated, and makes working with the data difficult:
  6 commentaires
Peng Li
Peng Li le 31 Mar 2020
@Stephen Cobeldick
Just a comment that the accumarray solution doesn't correctly deal with contiguous rows of NaNs, as as long as there are more than 1 contiguous rows of NaNs, cumsum will pick additional NaN rows, which results in a jump in idy(~idx). Therefore, the final C will contains cell elements that are empty. So additional steps are required to filter them. See an example modified based on yours:
M = [0,1;2,3;NaN,NaN;nan nan; nan nan; 4,5;6,7;NaN,NaN;8,9];
idx = all(isnan(M),2);
idy = 1+cumsum(idx);
idz = 1:size(M,1);
C = accumarray(idy(~idx),idz(~idx),[],@(r){M(r,:)})
C =
5×1 cell array
{2×2 double}
{0×0 double}
{0×0 double}
{2×2 double}
{1×2 double}
Andrew Sol
Andrew Sol le 21 Jan 2023
Thank you very much! It's very helpful!

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